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butalik [34]
3 years ago
11

Find the length of b to the nearest tenth using the Pythagorean theorem

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0

Answer:

11.2

Step-by-step explanation:

We can use the pythagorean theorem to find b.

the formula is as follows:

a^2 + b^2 = c^2

We are given a is 10 and c is 15, so we can plug those two numbers in:

10^2 + b^2 = 15^2

Now, we can simplify and solve:

100 + b^2 = 225

b^2 = 125

b = √125

√125 is about 11.1803398875, and to the nearest tenth, this rounds to:

11.2

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A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

4 0
4 years ago
Need help what is this
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Answer:

2nd option

Step-by-step explanation:

Substitute the values of x from the domain into f(x) for range

f(2) = 2³ + 1 = 8 + 1 = 9

f(3) = 3³ + 1 = 27 + 1 = 28

f(4) = 4³ + 1 = 64 + 1 = 65

range is {9, 28, 65 }

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2 years ago
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