Answer:
do you have a picture of the Graph?????
A / b + c
17.0079 / 2.05 + 3.1415926 =
8.29653658537 + 3.1415926 =
11.4381291854 <==
To find the length of the side, will take the under root of the area. So, the side will be :
c) 24.4 cm
Answer:
Communitive Property
Step-by-step explanation:
Commutative property = 2 + 3 = 3 + 2 or 2(3) = 3(2)
Associative Property = (2 x 3) 5 = 2 (3 x 5) or (2 + 3) + 5 = 2 + (3 + 5)
Inverse Property = 2 + (-2) = 0 or (2/1)(½) = 1
Basic Definitions:
<u><em>Commutative Property</em></u> - Gives you the ability to switch the order of the numbers in an expression.
<u><em>Associative Property</em></u> - Let's you move the parenthesis in an expression but not the numbers.
<u><em>Inverse</em></u> - Uses numbers like 0 and 1.
Using these basic definitions and examples, we can summarize that the best answer would be <u>Communitive Property</u>
<u></u>
Answer:
For 124 chirps per minute the temperature is 68 ºF.
For 68 chirps per minute the temperature is 54 ºF.
Step-by-step explanation:
Linear functions are those whose graph is a straight line. A linear function has the following form
![f(x)=b+mx](https://tex.z-dn.net/?f=f%28x%29%3Db%2Bmx)
b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.
m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.
We know that
- At 104 chirps per minute, the temperature is 63 ºF.
- At 176 chirps per minute, the temperature is 81 ºF.
This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and y = the temperature in ºF.
To find a linear function that let us find the outside temperature from how fast crickets chirp we must:
![m=\frac{y_2-y_1}{x_2-x_1}=\frac{81-63}{176-104}=\frac{1}{4}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%3D%5Cfrac%7B81-63%7D%7B176-104%7D%3D%5Cfrac%7B1%7D%7B4%7D)
![81=\frac{1}{4}\cdot 104+b](https://tex.z-dn.net/?f=81%3D%5Cfrac%7B1%7D%7B4%7D%5Ccdot%20104%2Bb)
Solving for b
![b=81-\frac{1}{4} (176)=37](https://tex.z-dn.net/?f=b%3D81-%5Cfrac%7B1%7D%7B4%7D%20%28176%29%3D37)
Therefore, the linear function is
![y=\frac{1}{4} \cdot x+37](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D%20%5Ccdot%20x%2B37)
Now, using this linear function we can know the temperature when we know the chirps per minute:
For 124 chirps per minute the temperature is:
![y=\frac{1}{4} \cdot (124)+37=68](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D%20%5Ccdot%20%28124%29%2B37%3D68)
For 68 chirps per minute the temperature is:
![y=\frac{1}{4} \cdot (68)+37=54](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B4%7D%20%5Ccdot%20%2868%29%2B37%3D54)