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Helen [10]
2 years ago
13

-3x+3y=9 2x−7y=−14 ​

Mathematics
1 answer:
nignag [31]2 years ago
6 0
Step: Solve
−
3
x
+
3
y
=
9
for x:
−
3
x
+
3
y
=
9
−
3
x
+
3
y
+
−
3
y
=
9
+
−
3
y
(Add -3y to both sides)
−
3
x
=
−
3
y
+
9
−
3
x
−
3
=
−
3
y
+
9
−
3
(Divide both sides by -3)
x
=
y
−
3

Step: Substitute
y
−
3
for
x
in
2
x
−
7
y
=
−
14
:
2
x
−
7
y
=
−
14
2
(
y
−
3
)
−
7
y
=
−
14
−
5
y
−
6
=
−
14
(Simplify both sides of the equation)
−
5
y
−
6
+
6
=
−
14
+
6
(Add 6 to both sides)
−
5
y
=
−
8
−
5
y
−
5
=
−
8
−
5
(Divide both sides by -5)
y
=
8
5

Step: Substitute
8
5
for
y
in
x
=
y
−
3
:
x
=
y
−
3
x
=
8
5
−
3
x
=
−
7
5
(Simplify both sides of the equation)

Answer:
X=-7/5 and y= 8/5
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stiks02 [169]
25•24•23=13,000 ways
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4 0
3 years ago
A square with side of k cm has perimeter of 36 cm. find the value of k.
Marrrta [24]

Answer: 9

Step-by-step explanation:

36/4 = 9


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5 0
2 years ago
HELP! 8TH GRADE MATH PLS LOL
LekaFEV [45]
<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

3 0
3 years ago
Which is a parallelogram with four congruent sides whose diagonals bisect each other and intersect at four right angles?
Charra [1.4K]

Answer:

I believe that the answer is B. Rhombus.

Step-by-step explanation:

A rhombus has the properties of a parallelogram and the diagonals intersect at right angles.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Determine the value of c so that f(x) is continuous on the entire real line when
mixer [17]

Answer:

A. -4

Step-by-step explanation:

Given the function f(x) = x + 3 for x ≤ -1 and 2x - c for x > -1, for the function to be continuous, the right hand limit of the function must be equal to its left hand limit.

For the left hand limit;

The function at the left hand occurs at x<-1

f-(x) = x+3

f-(-1) = -1+3

f-(-1) = 2

For the right hand limit, the function occurs at x>-1

f+(x) = 2x-c

f+(-1) = 2(-1)-c

f+(-1) = -2-c

For the function f(x) to be continuous on the entire real line at x = -1, then

f-(-1) = f+(-1)

On equating both sides:

2 = -2-c

Add 2 to both sides

2+2 = -2-c+2

4 =-c

Multiply both sides by minus.

-(-c) = -4

c = -4

Hence the value of c so that f(x) is continuous on the entire real line is -4

6 0
3 years ago
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