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lapo4ka [179]
3 years ago
5

What does |-71 equal?

Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer: 71

Step-by-step explanation:

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A researcher claims that the mean cost of raising a child from birth to age 2 by husband­wife families in the U.S. is $13,960. A
irina1246 [14]

Answer:

Yes, there enough evidence to reject the claim.

Step-by-step explanation:

Here we need to perform a test for single mean to determine whether the  mean cost of raising a child from birth to age 2 by husband-wife families in the U.S. is $13,960.

The hypothesis is:

<em>H₀</em>: The  mean cost of raising a child from birth to age 2 by husband-wife families in the U.S. is $13,960, i.e. µ = $13,960.

<em>Hₐ</em>: The  mean cost of raising a child from birth to age 2 by husband-wife families in the U.S. is different from $13,960, i.e. µ ≠ $13,960.

The information provided is:

\ar x=13725\\\sigma=2345\\n=500\\\alpha =0.10

The test statistic is:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{13725-13960}{2345/\sqrt{500}}=-2.24

The test statistic value is -2.24.

Compute the <em>p</em>-value for this test statistic value at 10% level of significance as follows:

p-value=2\times P(Z

               =2\times 0.01255\\=0.0251

Use the <em>z</em>-table.

The calculated <em>p</em>-value is, 0.0251 < 0.10, therefore the null hypothesis will be rejected.

<u>Conclusion</u>:

As the null hypothesis is rejected at 10% level of significance it can be concluded that there enough evidence to reject the claim.

The  mean cost of raising a child from birth to age 2 by husband-wife families in the U.S. is different from $13,960.

5 0
3 years ago
Help please I really really need this is my last question help hurry
den301095 [7]
1/6 is the answer. Good luck!
4 0
3 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

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