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Nana76 [90]
3 years ago
7

Here’s a freebie for anyone!

Mathematics
2 answers:
svetlana [45]3 years ago
7 0

Answer:

thank you

Step-by-step explanation:

elena-s [515]3 years ago
4 0

Answer:

fankssss

Step-by-step explanation:

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What is the remainder of 3,368,008 divided by 5574
zheka24 [161]
The answer is 604.235378543
4 0
3 years ago
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A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

                                                                                                            = $10,000

If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

⇒ The price of a one-way ticket that will maximize revenue is $7.50

7 0
3 years ago
7.Find the lengths of the missing sides in the triangle. If your answer is not an integer, leave it in simplest radical form. Th
Fed [463]

Here a right angled triangle given. one angle with measure 45^o given. The three sides of the triangle given 4, x, y.

We have to find, the sides which is opposite, adjacent and hypotenuse here.

We know that the side opposite to right angle is always hypotenuse. So, hypotenuyse = y.

The side adjacent to the given angle 45^o is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is sin(x) =\frac{Opposite}{Hypotenuse} , cos(x) =\frac{Adjacent}{Hypotenuse} , tan(x) =\frac{Opposite}{Adjacent}, where x is the angle given.

To get x, we will use tan. So we will get,

tan(45^o) = \frac{4}{x}

We know the value of tan(45^o) = 1. By substituting the value we will get,

1 =\frac{4}{x}

To find x, we have to move x here to the left side by multiplying it to both sides. We will get,

(1)(x) = (\frac{4}{x}) (x)

x = 4

So we have got the value of x here.

Now to find y, we will use the trigonometric function sine.

sin(45^o) =\frac{4}{y}

we know the value of sin(45^o) =\frac{\sqrt{2}}{2}

By substituting the value we will get,

\frac{\sqrt{2}}{2}  = \frac{4}{y}

By cross multiplying we will get,

(\sqrt{2}) (y) = (4)(2)

\sqrt{2}y = 8

We will get y by dividing both sides by \sqrt{2}, we will get,

\frac{\sqrt{2}y}{\sqrt{2}}   =\frac{8}{\sqrt{2} }

y =\frac{8}{\sqrt{2}  }

Now we will rationalize the denominator by multiplying \sqrt{2} to the top and bottom.

y =\frac{8\sqrt{2}}{(\sqrt{2})(\sqrt{2})}

y =\frac{8\sqrt{2}}{2}

y = 4\sqrt{2}

So we have got the required values of x and y.

8 0
3 years ago
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Can you please help me on this question 8(4-x)=7x+2
kati45 [8]

Answer:

2=x

Step-by-step explanation:

8(4-x)=7x+2

Distribute

32 - 8x = 7x+2

Add 8x to each side

32 - 8x+8x = 7x+8x+2

32 = 15x+2

Subtract 2 from each side

32-2 = 15x+2-2

30 = 15x

Divide each side by 15

30/15 = 15x/15

2 =x

5 0
3 years ago
HELP PLEASEEEEEEEEEeeeee
maks197457 [2]
Might have to experiment a bit to choose the right answer.

In A, the first term is 456 and the common difference is 10.  Each time we have a new term, the next one is the same except that 10 is added.

Suppose n were 1000.  Then we'd have 456 + (1000)(10) = 10456

In B, the first term is 5 and the common ratio is 3.  From 5 we get 15 by mult. 5 by 3.  Similarly, from 135 we get 405 by mult. 135 by 3.  This is a geom. series with first term 5 and common ratio 3.   a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.

Can you now examine C and D in the same manner, and then choose the greatest final value?  Safe to continue using n = 1000.





3 0
3 years ago
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