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iren2701 [21]
3 years ago
6

Help me please please help me

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

Go by the 5 times table and on

Step-by-step explanation:

There saying what numbers can you multiply to get ten.

once you find at least four/five of them, reverse it so it can be division.

Them use ether numbers you used to divide as your answer.

I hope this helps!  ✨

Liula [17]3 years ago
7 0
Go on the internet and do a 5x5 multiplication table
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In Exercises 9-14, decide whether enough information
Degger [83]

The triangles that can be proved to be congruent by the SAS Congruence Theorem are:

10. ΔLMN and ΔNQP

13. ΔEFH and ΔGHF

The triangles that cannot be proved to be congruent by the SAS Congruence Theorem due to insufficient information are:

9. ΔABD and ΔCDB

12. ΔQRV and ΔTSU

14. ΔKLM and ΔMNK

11. ΔYXZ and ΔWXZ

<h3>What is the SAS Congruence Theorem?</h3>
  • If two triangles have two pairs of corresponding sides that are congruent, and a pair of corresponding included angle that are congruent, both triangles can be proven to be congruent triangles by the SAS Congruence Theorem.

Thus:

9. ΔABD and ΔCDB have:

  • one pair of congruent <em>non-included angles </em>- ∠ABD ≅ ∠CDB
  • two pairs of congruent sides - AD ≅ BC, and BD ≅ BD

ΔABD and ΔCDB lack a pair of <em>included angles</em>, therefore, the information given is not enough to prove the triangles are congruent by the SAS Congruence Theorem.

10. ΔLMN and ΔNQP have:

  • one pair of congruent <em>included angles </em>- ∠LMN ≅ ∠NQP
  • two pairs of congruent sides - LM ≅ NQ, and MN ≅ QP

ΔLMN and ΔNQP, therefore, have enough information to prove that they are congruent triangles by the SAS Congruence Theorem.

11. ΔYXZ and ΔWXZ have:

  • one pair of congruent <em>non-included angles </em>- ∠YXZ ≅ ∠WXZ
  • two pairs of congruent sides - XZ ≅ XZ, and XW ≅ YZ

ΔYXZ and ΔWXZ lack a pair of <em>included angles</em>, therefore, the information given is not enough to prove the triangles are congruent by the SAS Congruence Theorem.

12. ΔQRV and ΔTSU do not have enough information to prove they are congruent by the SAS Congruence Theorem.

13. ΔEFH and ΔGHF have two pairs of congruent sides and a pair of congruent <em>included angles</em><em>, </em>therefore, there is enough information to prove they are congruent by the SAS Congruence Theorem.

14. ΔKLM and ΔMNK do not have enough information to prove they are congruent by the SAS Congruence Theorem.

Therefore, the triangles that can be proved to be congruent by the SAS Congruence Theorem are:

10. ΔLMN and ΔNQP

13. ΔEFH and ΔGHF

The triangles that cannot be proved to be congruent by the SAS Congruence Theorem due to insufficient information are:

9. ΔABD and ΔCDB

12. ΔQRV and ΔTSU

14. ΔKLM and ΔMNK

11. ΔYXZ and ΔWXZ

Learn more about SAS Congruence Theorem on:

brainly.com/question/13408604

3 0
3 years ago
Let g(x) be the reflection of f(x) = x2 +3 in the x-axis. What is the function rule for g(x)? A. g(x) = -x2 - 3 B. g(x) = -x2 +
Mandarinka [93]
If it is its reflection it means it its opposite. To determine an opposite, you can put - in front of the ecuation ( or number). So -( x2+3)=-x2-3
the correct answer is A
3 0
3 years ago
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Suppose you roll a special 33 sided die. What is the probability that the number rolled is a one or a two?
Pepsi [2]

Answer:

2/33

Step-by-step explanation:

Chance of rolling a 1 is 1/33, chance of rolling a 2 is also 1/33. so add the probabilities 1/33 + 1/33 =2/33

4 0
3 years ago
On a piece of paper, use a protractor to construct a triangle with angle measures of 30° and 50º. What is the measure of the thi
kolezko [41]
Sum of the angles of a triangle is 180 degrees.
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Help urgent In a class of 35 students 15 of them have cats 16 have dogs 3 hangs none how many probability does have both
dalvyx [7]

Answer:

9/25

Step-by-step explanation:

Number of student who has cat , dog = 25 - 3 = 22

Number of students who has cat and dogs = (15 + 16) - 22

                                                                       = 31 - 22 = 9

Number of students who has only cats = 15 - 9 = 6

Number of students who has only dogs = 16 - 9 = 7

P(Cat & dog) = 9/25

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