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lora16 [44]
2 years ago
12

Help me with it I will give you 20 points ​

Mathematics
1 answer:
cupoosta [38]2 years ago
4 0

Answer:

a^2 +b^2=c^2

Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)

We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2

) is given by m= x 2−x 1

y

2

​

−y

1

​

​

,x

2

​



=x

1

​

Slope of AB i.e.m

1

​

=

3−4

5−4

​

=−1

Slope of BC i.e.m

2

​

=

−1−3

−1−5

​

=

−4

−6

​

=

2

3

​

Slope of CA i.e. m

3

​

=

4+1

4+1

​

=

5

5

​

=1

Clearly, m

1

​

m

3

​

=−1

⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).

Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.

Step-by-step explanation:

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What are the solutions of the system?
svetlana [45]

Answer:

Option C. No solution is the right answer.

Step-by-step explanation:

Here the given equations are y = x²+2x+3 -----(1)

and y = 4x-2 -------(2)

Now we substitute the value of y from equation 2 into 1.

x²+2x+3 = 4x-2

x²+2x+3-2x = 4x-2-2x

x²+3 = 2x-2

x²+3-2x = 2x-2x-2

x²-2x+3 = -2

x²-2x+5 = 0

Then value of x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

=\frac{+2\pm \sqrt{4-4\times 1\times 5}}{2}

=\frac{2\pm \sqrt{4-20}}{2}

Since in this solution √(-20) is not defined. Therefore there is no solution.

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2 years ago
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Grace [21]

Answer:

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Step-by-step explanation:

Given

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Step-by-step explanation:

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Step-by-step explanation:

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