I-ready test 7th grade

Determine the sign of the leading coefficient

9966 [12]

Answer:

negative

Step-by-step explanation:

The graph falls to both the left and right, so the leading coefficient has to be negative, and it must be raised to an even power.

7 0

2 years ago

Pease help, thank you

andreyandreev [35.5K]

Answer: -2

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Draw a vertical line through 4 on the x axis. This vertical line crosses the parabola at some point (which we'll call point A). Draw a horizontal line from point A to the y axis and note how it lands on y = 12. Therefore the point (4,12) is on this parabola.

Repeat the same steps as before to find that (8,4) is also on the parabola

We need to find the slope of the line through (4,12) and (8,4)

m = (y2 - y1)/(x2 - x1)

m = (4-12)/(8 - 4)

m = -8/4

m = -2

The slope of this line is -2 meaning that the average rate of change from x = 4 to x = 8 is -2.

The line goes down 2 units each time you move to the right 1 unit.

6 0

3 years ago

Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28

Dafna1 [17]

The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)

By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C

7 0

3 years ago

Find the inequality represented by the graph - khan academy<br> PLEASE HELP

Andru [333]

Answer:

y ≤ x - 1

Step-by-step explanation:

The slope is 1 (every unit for x, there is a unit for y, rise/run is 1/1). The y-intercept is -1, because the line crosses the y-axis at -1. The graph is shaded below the line, and the line is solid, meaning that y is less than or equal to x -1, or y ≤ x - 1.

5 0

2 years ago

, list the first five terms of each sequence, and identify them as arithmetic or geometric.

Serhud [2]

Answer:

The first 5 terms are -6,-25,-44,-63 and -82

The sequence is arithmetic

Step-by-step explanation:

Given that A(n + 1) = A(n) − 19 for n ≥ 1 and A(1) = −6

A(1) = -6

A(2) = A(1) − 19 = -6 - 19 = -25

A(3) = A(2) − 19 = -25 - 19 = -44

A(4) = A(3) − 19 = -44 - 19 = -63

A(5) = A(4) − 19 = -63 - 19 = -82

So the first 5 terms are -6,-25,-44,-63 and -82

If they are in arithmetic the common difference will be same, if geometric common ratio will be same.

Let us check common difference,

-25-(-6) = -19

-44-(-25) = -19

-63-(-44) = -19

-82-(-63) = -19

So common difference is same, so the sequence is arithmetic.

3 0

3 years ago