All categories

2 years ago

Help me please thank you

Mathematics

1 answer:

nordsb [41]2 years ago

3 0

Answer:

I believe the answer is linear.

Step-by-step explanation:

The relationship between x and y is a difference of 3 each time either side goes up, and that is linear. If it was exponential it would go up in a different number each time.

Hope this helped!

You might be interested in

Persuade Mr.Zorn whether the numbers 12, 16, and 20 make a right triangle or not. make sure to state reasons for and against you

TEA [102]

Answer:

They don’t 12+16+20= 48

12 x 16 x 20= 3840

Step-by-step explanation:

3 0

2 years ago

The price of 25 tickets is $2705 dollars. Find the price of 8 tickets

mojhsa [17]

Answer:

Step-by-step explanation:

25 tickets = $2705

1 ticket = $\frac{2705}{25}$

= $108.20

8 tickets= 108.20×8

=$865.60

7 0

3 years ago

Read 2 more answers

QUIZ<br> Find the volume of the square pyramid.<br> 9 cm<br> 4 cm

kari74 [83]

Answer:

SEE BELOW

Step-by-step explanation:

V=a²h/3
=9² x 4/3
= 81 x 4/3
= 27 x 4
= 108 cm³

5 0

2 years ago

Please help!! i need this asap

kompoz [17]

I would help but I cannot read it.

3 0

3 years ago

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0

3 years ago