3 years ago

Pleaseeeeee answerrrrrrrrrrrr

1 answer:

3 0

The answer is b
Its b because you distributed
4(4a+5)
You multiplied 4x4a and you got
16a+4(5)
Which 4x5 is 20
So its 16a+20

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Find all real and complex roots of the equation below x^4-81=0

Pepsi [2]

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3 years ago

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2 years ago

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3 years ago

The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Dominik [7]

Answer:

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

Step-by-step explanation:

Given

$(x_1,y_1,z_1) = (1,3,-2)$

$(x_2,y_2,z_2) = (4,5,0)$

$(x_3,y_3,z_3) = (6,3,9)$

Required

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Represent the coordinates with C.

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$C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))$

Substitute values of x and y in the given equation

$C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))$

$C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))$

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

<em>The above is the coordinate of the centroid</em>

8 0

3 years ago