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sertanlavr [38]
3 years ago
12

Classify the triangle formed by these three sides 5, 12, 15

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0

Answer:

Right

Step-by-step explanation:

whenever you draw it and you have 15 as the hypotenuse and 12 and 5 as the legs it makes sense.

Charra [1.4K]3 years ago
4 0

Answer:

obtuse

Step-by-step explanation:

Given 3 sides of a triangle a, b, c ( where c is the longest ) , then

• If a² + b² = c² ⇒ right

• If a² + b² > c² ⇒ acute

• If a² + b² < c² ⇒ obtuse

Here c = 15 , then c² = 15² = 225

5² + 12² = 25 + 144 = 169

Since 5² + 12² < 15² then triangle is obtuse

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A recipe that yields 12 cups of soup calls for 28ounces of beef broth. How many ounces of beef broth do you need to make 18 cups
babymother [125]
We will ratio to solve this problem.
Given the first information, we know that for 12 cups of soup, there are 28 oz of beef broth. This can be expressed as 28/12.

With the second information, we know that for 18 cups of soup, there is x amount of beef broth. This can be expressed as x/18
In this case, x stands for broth.

Because these are ratios, we know they will equal each other. We can set up this as an equation.
28/12=x/18
Solve for x
28/12=x/18
28/12 can be simplified to 7/4
7/4 • 18= x
126/4 = x
31.5= x
ANSWER:
31.5 oz of beef broth is needed to make 18 cups of soup
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4 years ago
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3 years ago
52 of 85 is what amount
vitfil [10]
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6 0
3 years ago
Find the equation of the line that passes throughP(6,0) andQ(1,−1).
yarga [219]

Answer:

Step-by-step explanation:

y=mx+b where m is the slope and b is the y intercept

m=(y2-y1)/(x2-x1), we have points (6,0) and (1,-1)

m=(-1-0)/(1-6)=1/5 so we have

y=x/5+b, using point (6,0) we can solve for b

0=6/5+b

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5 0
3 years ago
How to solve it ...<br><br>1. 5-2x²-6x<br>2. (x+3) (x+4)=0
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1.\\5-2x^2-6x=0\\-2x^2-6x+5=0\\\\a=-2;\ b=-6;\ c=5\\\\\Delta=b^2-4ac\to\Delta=(-6)^2-4\cdot(-2)\cdot5=36+40=76\\\\x_1=\frac{-b-\sqrt\Delta}{2a}\to x_1=\frac{6-\sqrt{78}}{2\cdot(-2)}=\frac{6-\sqrt{4\cdot19}}{-4}=\frac{6-2\sqrt{19}}{-4}=\frac{\sqrt{19}-3}{2}\\\\x_2=\frac{-b+\sqrt\Delta}{2a}\to x_2=\frac{3-\sqrt{19}}{2}

=============================================================

2.\\(x+3)(x+4)=0\iff x+3=0\ \vee\ x+4=0\\\\x=-3\ \vee\ x=-4
8 0
3 years ago
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