Answer:
1 La longitud de las nuevas cuerdas = 5 metros y 9 metros
2 El costo de las paletas = $ 3
El costo de las gomitas = $ 3
Step-by-step explanation:
1) Sea la primera mitad de la cuerda representada por = a
Deje que la segunda mitad de la parte superior esté representada por = b
a + b = 14 metros
De la pregunta, se nos dice que ok, la mitad es 4 metros más larga que la otra
a = b + 4
Por lo tanto
b + 4 + b = 14 metros
2b + 4 = 14 metros
2b = 14 - 4
b = 10/2
b = 5 metros
a = b + 4
a = 5+ 4
a = 9 metros
Por lo tanto, la longitud de las nuevas cuerdas = 5 metros y 9 metros
2)
Representemos el costo de las paletas = p
Costo de gomitas = g
De la pregunta 2 se nos dice que:
Tu vas a la tienda con un amigo y compras 6 paletas y 2 gomitas. Si tú pagas $ 24
Por tanto: 6p + 2g = 24 ....... Ecuación 1
Tu amigo pide 1 paleta y 10 gomitas. y tu amigo $ 33
p + 10g = 33 ....... Ecuación 2
p = 33 - 10g
Sustituya p por 33 - 10g en la Ecuación 1
6p + 2g = 24 ....... Ecuación
6 (33-10 g) + 2 g = 24
198 - 60 g + 2 g = 24
-58g = 24-198
-58g = - 174
g = -174 / -58
g = $ 3
Para encontrar p
p = 33 - 10g
p = 33 - 10 × 3
p = 33 - 30
p = $ 3
Por lo tant,
El costo de las paletas = $ 3
El costo de las gomitas = $ 3
Answer:

Step-by-step explanation:
As x approaches 10 from the right side, h(x) approaches 18.5 but never touches it.
10% of $20 is $2 (take off the end 0)
$20+10%=?
$20+$2[this is 10%]=$22
The selling price is $22
Answer:
12
Step-by-step explanation:
The answer is 12 because there are 12 different months in a year and also all the attendees must have birthdays in different months and not in the Same month. Hence 12 the largest possible number of attendees
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.