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Naily [24]
3 years ago
6

Melvin has $25 dollars to spend. He spent $10.81, including tax, to buy a new DVD. He needs to save $10.00 but he also wants to

buy peanuts. Peanuts cost $0.38 per package including tax.
Write and solve an inequality that will determine the maximum number of packages of peanuts that Melvin can buy
Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

Melvin can buy 11 package Peanuts

Step-by-step explanation:

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Which operation will make the llower left element the largest?
algol [13]

Answer:

R2->R3

Step-by-step explanation:

3 0
3 years ago
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HELP ASAP PLEASE NO LINKS. Mike invests $33,000 with an interest rate of 5.5% compounded quarterly. After 5 years, what is the t
melamori03 [73]
($43,364.19)Rounded to the nearest cent=($43,364.20)
8 0
3 years ago
While shopping for school Janice and Patty spent more than $175. Janice spent $34. How much did Patty spend?
Natali [406]

Answer:

At least $141

Step-by-step explanation:

175-34=141

7 0
4 years ago
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Bryce buys a treadmill online for $510. If shipping and handling are an additional 21 <img src="https://tex.z-dn.net/?f=%5Cfrac%
scZoUnD [109]

Answer:

The shipping and handling charge that Bryce paid is $109.65

Step-by-step explanation:

Given as :

The online price of the treadmill = $510

The charge of shipping and handling = 21\dfrac{1}{2} % of online price

Let The shipping and handling charge that Bryce paid = $x

<u>Now, According to question</u>

∵ The charge of shipping and handling = 21\dfrac{1}{2} % of online price

So, x = \dfrac{43}{2} % of $510

Or, x = \dfrac{43\times 510}{100\times 2}

Or, x = $109.65

The shipping and handling charge that Bryce paid = x = $109.65

Hence,The shipping and handling charge that Bryce paid is $109.65 Answer

7 0
3 years ago
Can someone help me pls
docker41 [41]

Answer:

See below

Step-by-step explanation:

For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.

So,

{10}^{2}  +  {6}^{2}  = 100 + 36 = 136 \\  \\  {12}^{2}  = 144 \\  \\  \because \:  {10}^{2}  +  {6}^{2}    \neq \:  {12}^{2}  \\

From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.

6 0
3 years ago
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