Question

Can someone help me pls

Answer 1

Answer:

See below

Step-by-step explanation:

For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.

So,

${10}^{2} + {6}^{2} = 100 + 36 = 136 \\ \\ {12}^{2} = 144 \\ \\ \because \: {10}^{2} + {6}^{2} \neq \: {12}^{2}$

From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.