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Sloan [31]
3 years ago
5

Can someone help me pls

Mathematics
1 answer:
docker41 [41]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.

So,

{10}^{2}  +  {6}^{2}  = 100 + 36 = 136 \\  \\  {12}^{2}  = 144 \\  \\  \because \:  {10}^{2}  +  {6}^{2}    \neq \:  {12}^{2}  \\

From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.

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-------------------------------

Explanation:

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