Can someone help me pls
1 answer:
Answer:
See below
Step-by-step explanation:
For seg FG to be tangent to the circle with center E, the side lengths 6, 10, 12 must follow the rule of Pythagorean triplets.
So,
From above it is obvious that given segment lengths doesn't follow the Pythagorean triplet rule. Therefore, seg FG is not tangent to the circle with center E.
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Answer:
, 
Explanation:
2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) =
sin(q) =
Now, we know that:
sin (45) =
From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to
or q = 270 + 45 = 315° which is equivalent to
Hope this helps :)
Explanation:
2√2 sin(q) + 2 = 0
2√2 sin(q) = -2
sin(q) =
sin(q) =
Now, we know that:
sin (45) =
From the ASTC rule, we know that the sine function is negative in the third and fourth quadrant.
This means that:
either q = 90 + 45 = 135° which is equivalent to
or q = 270 + 45 = 315° which is equivalent to
Hope this helps :)