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marusya05 [52]
3 years ago
5

Find the missing angle.

Mathematics
2 answers:
maw [93]3 years ago
4 0

Answer:

45°

Step-by-step explanation:

All angles in a triangle add up to 180°

180 - (90 + 45)

= 180 - 135

= 45

Therefore the missing angle is 45°

Doss [256]3 years ago
3 0

Answer:  answer is 45

Step-by-step explanation:

I added 90 with 45, got 135, then subtracted 180 with 135...

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Answer:

<em>Initial population: 222 fish</em>

<em>After 7 years: 871 fish</em>

Step-by-step explanation:

Initial population size:

Let t=0

∴P(0)=\frac{2000}{1+8e^0}

       =\frac{2000}{1+8}

       =\frac{2000}{9}

       =222 fish

After 7 years:

Let t=7

∴P(7)=871 fish

6 0
2 years ago
Help me with this one
Afina-wow [57]

Answer:

SSS

Step-by-step explanation:

We can see that 2 sides are equal already, and because they share a side, that side is also equal. So, side side side.

6 0
3 years ago
Please help! Been stuck on this for hours Solve the inequality. Express your answer in interval form. (If there is no solution,
yawa3891 [41]

Answer:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

Step-by-step explanation:

The inequality resolves into 4 inequalities. There are 4 intervals in the solution.

Starting at the left, for the absolute value argument less than 0:

  2 ≤ -(x^2 -4) . . . . . . . for x^2 -4 ≤ 0

  2 ≤ -x^2 +4

  -2 ≤ -x^2

  2 ≥ x^2 . . . . . . . . . . consistent with the above 4 ≥ x^2

  -√2 ≤ x ≤ √2 . . . . . square root; may be limited by other constraints

For the absolute value argument greater than 0:

  2 ≤ x^2 -4 . . . . . . . for x^2 -4 ≥ 0

  6 ≤ x^2 . . . . . . . . . .consistent with x^2 ≥ 4

  -√6 ≥ x ∪ x ≤ √6 . . . . take the square root

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The inequality on the right can be written as the compound inequality ...

  -4 < x^2 -4 < 4

  0 < x^2 < 8 . . . . . add 4

  0 < |x| < √8 . . . . take the square root

This resolves to ...

  -√8 < x < 0 ∪ 0 < x < √8

__

So, the solution set is the set of values of x that satisfy these restrictions on x:

  -√2 ≤ x ≤ √2

  x ≤ -√6 ∪ x ≤ √6

  -√8 < x < 0 ∪ 0 < x < √8

That is a collection of 4 intervals:

  (-√8, -√6] ∪ [-√2, 0) ∪ (0, √2] ∪ [√6, √8)

_____

You may be expected to write √8 as 2√2.

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These intervals are the portions of the red curve that lie between the two horizontal lines. The points on the upper (dashed) line are not part of the solution set. The points on the lower (solid) line are part of the solution set.

7 0
3 years ago
Use rectangle ABCD and the given information to solve each problem.
solong [7]

Problem 1

<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>

--------------------

Work Shown:

point E = intersection point of diagonals.

x = measure of angle 6

y = measure of angle 8

angle 7 is also x because triangle AED is isosceles (AE = ED)

Focus on triangle AED, the three angles A, E, D add to 180

A+E+D = 180

x+80+x = 180

2x+80 = 180

2x = 180-80

2x = 100

x = 100/2

x = 50

So both angles 6 and 7 are 50 degrees.

Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.

(angle7)+(angle8) = 90

50+y = 90

y = 90-50

y = 40

angle 8 = 40 degrees

=================================================

Problem 2

<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>

--------------------

Work Shown:

Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)

angle 3 and angle 4 form a 90 degree angle

x = measure of angle 3

(angle 3)+(angle 4) = 90

x+29 = 90

x = 90-29

x = 61

Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.

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Answer:

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Step-by-step explanation:

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