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3 years ago

Find the slope of a line through the points (-5, 2) and (-5, 4).

Mathematics

2 answers:

valkas [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

= (4-2)/(-5-(-5))

= 2/0

Which is undefined

Alternately,

Since both points have x-coordinate of -5, they lie on the line x = -5

which is a vertical line (parallel to y-axis).

Every vertical line has an undefined slope

dybincka [34]3 years ago

6 0

The slope is undefined, because the x values are the same.

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Which of these is incorrect? A) 41,792 < 42,699 B) 42,699 > 43,595 Eliminate C) 42,699 < 44,792 D) 43,595 > 41,792

eimsori [14]

B is the correct answer

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3 years ago

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CALC- limits<br> please show your method

gladu [14]

A. Factor the numerator as a difference of squares:

$\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6$

c. As $x\to\infty$ , the contribution of the terms of degree less than 2 becomes negligible, which means we can write

$\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4$

e. Let's first rewrite the root terms with rational exponents:

$\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}$

Next we rationalize the numerator and denominator. We do so by recalling

$(a-b)(a+b)=a^2-b^2$
$(a-b)(a^2+ab+b^2)=a^3-b^3$

In particular,

$(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3$
$(x^{1/2}-x)(x^{1/2}+x)=x-x^2$

so we have

$\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}$

For $x\neq0$ and $x\neq1$ , we can simplify the first term:

$\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x$

So our limit becomes

$\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43$

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3 years ago

Brandon completed 12/1/2 problems in 50 minutes

Goshia [24]

Answer:

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Step-by-step explanation:

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2 years ago

Solve for x. The polygons in each pair are similar.

VMariaS [17]

Answer:

x = 9

Step-by-step explanation:

We need to find the value of x if the polygons in each pair are similar.

As they are similar, the ratio of their sides are equal.

The sides of first polygon are 6,12 and 4.8. On the other hand, the sides of second polygon are (2x-9) and 18.

So,

$\dfrac{6}{2x-9}=\dfrac{12}{18}\\\\\dfrac{6}{2x-9}=\dfrac{2}{3}\\\\\dfrac{3}{2x-9}=\dfrac{1}{3}\\\\x=9$

So, the value of x is equal to 9.

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3 years ago

What is the following quotient? 6-3(3 √8)/3 √9

WARRIOR [948]

Answer:

Factor the numerator and denominator and cancel the common factors.

Exact Form:

√

−

√

Decimal Form:

0.26375774

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3 years ago

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