Please help quick for 25 points with explanations. Any silly and absurd answers will be reported.
1 answer:
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
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ANSWER
E. 10 and 640
EXPLANATION
The given series is
To find the first term of the series we substitute i=1 to get,
For the last term of the series, we substitute i=4 to obtain,
This implies that,
Therefore the correct answer is E
E. 10 and 640
EXPLANATION
The given series is
To find the first term of the series we substitute i=1 to get,
For the last term of the series, we substitute i=4 to obtain,
This implies that,
Therefore the correct answer is E