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rosijanka [135]
2 years ago
8

A mirror with a parabolic cross section is used to collect sunlight on a pipe located at the focus of the mirror. The pipe is lo

cated 2 inches from the vertex of the mirror. Write an equation of the parabola that models the cross section of the mirror. Assume that the parabola opens upward.
Mathematics
1 answer:
prisoha [69]2 years ago
6 0

The answer is y= 1/8x^2, if you are using Connexus the answer is C.

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Answer:

Option B is correct .

Step-by-step explanation:

According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .

And ,the given function is ,

\implies f(x) = 4 - x^2 \\\\\implies f(x) = 4-x^2=0 \\\\\implies 2^2-x^2=0\\\\\implies (2-x)(2+x) = 0 \\\\\boxed{\red{\bf \implies x = 2 , (-2) }}

<u>Hence ,we can can see that x = </u><u> </u><u>2</u><u> </u><u>and</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>zeroes </u><u>of </u><u>graph</u><u>. </u><u> </u>

This implies that if we know the zeroes , we can frame the Equation.

On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.

\implies g(x) = (x-\alpha)(x-\beta) \\\\\implies g(x) = (1+x)(1-x) \\\\\boxed{\pink{\bf \implies g(x) = 1 - x^2}}

<u>Hence </u><u>option </u><u>B</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u>

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