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rosijanka [135]
3 years ago
8

A mirror with a parabolic cross section is used to collect sunlight on a pipe located at the focus of the mirror. The pipe is lo

cated 2 inches from the vertex of the mirror. Write an equation of the parabola that models the cross section of the mirror. Assume that the parabola opens upward.
Mathematics
1 answer:
prisoha [69]3 years ago
6 0

The answer is y= 1/8x^2, if you are using Connexus the answer is C.

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how many x-intercepts will the graph of y=(x-2)^2 have?
tekilochka [14]

Answer:

1

Step-by-step explanation:

Because it y is 0 then we can find the X intercepts. so there will be one X intercept.

4 0
3 years ago
Caitlin is making cookies. She makes 2 batches of cookies on
zlopas [31]
2 and a half cups of chocolate I think
7 0
3 years ago
Read 2 more answers
Anyone know how to do this? Please help
denpristay [2]

Answer:

93.6 inch^2

Step-by-step explanation:

sides=6 side-length=6 inches Apothem= 5.2 inches Area= 6*(1/2)(6)(5.2)

3 0
3 years ago
huong and kathyrn each day impeoved their yards by planting rose bushes and ornamental grass. they bought their supplies from th
marta [7]

Answer:

One rose bush = $3

One bunch of ornamental grass = $4

Step-by-step explanation:

We can set up a system of equations to solve for this. Let cost of 1 rose bush be r and cost of 1 ornamental grass be g. Thus we can form 2 equations:

14r+7g=70\\5r+14g=71

We can multiply the first equation by -2 so that we can eliminate g. Thus, we have:

(*-2)14r+7g=70\\5r+14g=71\\-------\\-28r-14g=-140\\5r+14g=71\\--------\\-23r=-69\\r=\frac{-69}{-23}=3

Thus, 1 rose bush is $3. Now plugging in r = 3 into the first original equation, we can solve for g:

14r+7g=70\\14(3)+7g=70\\42+7g=70\\7g=70-42\\7g=28\\g=\frac{28}{7}=4

Thus, 1 bunch of ornamental grass is $4.

5 0
3 years ago
There are 20 small tropical fish swimming in a 55-gallon aquarium. What is the population density?
umka21 [38]

Answer:

The population density is 0.364 fish per gallon.

Step-by-step explanation:

The population density can be defined as the number of individuals (in this case, small tropical fish) per unit of area or volume. In this case, the volume of the aquarium (55 gallon).

The density can be calculated then as:

d=\dfrac{P}{V}=\dfrac{20\;\text{fish}}{55\;\text{gal}}\approx0.364\dfrac{\text{fish}}{\text{gal}}

The population density is 0.364 fish per gallon.

5 0
3 years ago
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