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3 years ago

What's 3 3/4 - 7/8? (please help i’m too lazy to do it)

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

4 0

The answer is 2.875

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Find the square root of :<br> √50×8 = ___<br> Please show steps....

Sav [38]

Your answer would be 20.. the square root of 50 is 7.07106781187 x by 8

6 0

3 years ago

Jina had 7/8 of a spool of yarn.she used 3/4 of it for her project.What fraction of the spool was used for her project

Sophie [7]

7/8 * 3/4 = 21/32

She used 21/32 of a spool

7 0

3 years ago

Landon used a semicircle, a rectangle, and a right triangle to form the figure below. Which is the best estimate of the area of

Damm [24]

Answer:

38.28cm^2

Step-by-step explanation:

Area of rectangle = 24cm^2

Area of rectangle = 8cm^2

Area of semicircle = 6.28cm^2

4 0

4 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Find the value of x.

Mariana [72]

Answer:

Step-by-step explanation:

sin^-1(7/16)= 25.9 degrees

7 0

3 years ago