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Travka [436]
3 years ago
10

You previously found the mean of this data set. Use that in answering the question. 63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25,

93, 22, 90, 79 Calculate the sum of squares of the data set.
Mathematics
1 answer:
kicyunya [14]3 years ago
3 0

Answer:

Sum of squares of differences = 11239.74

Step-by-step explanation:

We are given the following data set:

63, 89, 92, 73, 79, 72, 34, 36, 94, 21, 25, 93, 22, 90, 79

We have to calculate the sum of square of the data set.

Formula:

\text{Sum of square of differences} = \sum (x_i -\bar{x})^2

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{962}{15} = 64.13

Sum of squares of differences =

1.284444444 + 618.3511113 + 776.5511113 + 78.61777778 + 221.0177779 + 61.88444445 + 908.0177776 + 791.4844443 + 892.017778 + 1860.484444 + 1531.417778 + 833.2844446 + 1775.217777 + 669.0844446 + 221.0177779

= 11239.74

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Step-by-step explanation:

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7 0
3 years ago
Problem 1: Use the Laplace Transforms to solve:
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Transforming the ODE yields

L\left\{y'' - y'\right\} = L\left\{e^{-3t}\right\}

(s^2 Y(s) - sy(0) - y'(0)) - (s Y(s) - y(0)) = \dfrac1{s+3}

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Partial fractions:

Y(s) = \dfrac as + \dfrac b{s-1} + \dfrac c{s+3}

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Take the inverse transform:

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2 years ago
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4 years ago
John is 5 years older than Sam and the product of their ages is 300. How old is Sam ?
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