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4 years ago

Can watermelon be measured in grams

Mathematics

2 answers:

Natalija [7]4 years ago

6 0

Anything can be measured in trams lol

tia_tia [17]4 years ago

4 0

Grams are used to measure the mass or weight of an object, so yes, a watermelon can be measured in grams.

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Two angles form a linear pair. One angle measures (10x - 63). The other angle measures (8x)". What is the value of the larger

EleoNora [17]

Answer:

108 degrees

Step-by-step explanation:

Given

Let the angles be A and B

$A = 10x - 63$

$B = 8x$

Required

Find the larger angle

If both angles form linear pair, then the following relationship exist:

$A + B = 180$

Substitute values for A and B

$10x - 63 + 8x = 180$

Collect Like Terms

$10x + 8x = 180 + 63$

$18x = 243$

Solve for x

$x = \frac{243}{18}$

$x = 13.5$

Substitute 13.5 for x in

$A = 10x - 63$

$B = 8x$

$A= 10 * 13.5 - 63$

$A= 135 - 63$

$A= 72$

$B = 8 * 13.5$

$B = 108$

<em>Hence, the larger angle measures 108</em>

4 0

3 years ago

0.87 written as a fraction is _____. 8/9 79/90 81/90

makvit [3.9K]

0.87= 87/100

But there is no choice even though it is the right answer

Answer is 87/100

8 0

3 years ago

WANT to keep making easy 30pts and brainliest??!!!!

earnstyle [38]

F ,B ,J are the answers

3 0

3 years ago

Read 2 more answers

If it takes 3 feet and 10 inches of wood to make a doll house, how much wood do you need to make 6 doll houses ?

S_A_V [24]

The answer is 23 hope this helps

7 0

2 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0

3 years ago