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kotykmax [81]
3 years ago
11

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

69 with a population standard deviation of 3.23. What is the 95% confidence interval for the amount of time spent on administrative issues?
Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

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Answer:

A.

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Step-by-step explanation:

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Range is the amount of y values

_______________________________

Domain:

Starts from -4 to 4

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I made the sign less than or equal to because the circle lines are solid.

Range:

This starts from -4 to 4 also.

{-4 ≤ y ≤ 4}

<em>Thus,</em>

<em>answer choices A. is correct</em>

<em />

<em>Hope this helps :)</em>

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