The outer electron in magnesium is excited by absorbing the heat energy from the N=1 stage to higher energy levels when it starts to drop back down to the N=2 level it losses energy in the form of visible light this is part of the Balmer series
hope that helps
Answer: 94.07%
Explanation:
Percentage yield can be calculated by the formula
%yield = Experimental yield/Theoretical yield x100
Experimental yield = 7.93g
Theoretical yield = 8.43
%yield = Experimental yield/Theoretical yield x100
%yield = 7.93/8.43 x 100 = 94.07%
Density is the mass divided by the volume of the object
you know denisty and you know mass so you can determine volume if you rearrange the formula
however, when you're doing the division, make sure the units match, since density is given in grams and mass is given in kilograms
once you have volume in cm3, convert that into "dl"
<u>Answer:</u> The mass of manganese(III) oxide produced is 113.03 g
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of zinc = 46.8 g
Molar mass of zinc = 65.38 g/mol
Plugging values in equation 1:
The given chemical equation follows:
By the stoichiometry of the reaction:
If 1 mole of zinc produces 1 mole of manganese(III) oxide
So, 0.716 moles of zinc will produce = of manganese(III) oxide
Molar mass of manganese(III) oxide = 157.87 g/mol
Plugging values in equation 1:
Hence, the mass of manganese(III) oxide produced is 113.03 g
#2 is solid because most exist naturally as solids