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grigory [225]
3 years ago
10

The photographs show comb jellies and an anglerfish in a benthic ecosystem

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
8 0

The organism in the bethic zone can survive in such high pressure area. This is because the organism there have no air pockets that provides them the ability to be balanced in the water

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Study the scenario. The particles in a system are moving around very slowly. A few minutes later, the particles are moving, on a
Bogdan [553]

Answer:

The average kinetic energy of the system has increased as a result of the temperature increasing.

Explanation:

Assuming this is a gas based on the framing.

The molecules of a gas span a distribution of speeds, and the average kinetic energy of the molecules is directly proportional to the absolute temperature of the sample. KEavg is proportional to T.

This can be further studied until the Kinetic-Molecular Theory.

4 0
3 years ago
When 21.45 g of KNO3 was dissolved in water in a calorimeter, the temperature fell from 25.00°C to 14.14 °C. If the heat capacit
pashok25 [27]

25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)

<h3>Explanation</h3>

The process:

\text{KNO}_3\;(s) \to \text{KNO}_3\;(aq).

How many moles of this process?

Relative atomic mass from a modern periodic table:

  • K: 39.098;
  • N: 14.007;
  • O: 15.999.

Molar mass of \text{KNO}_3:

M(\text{KNO}_3) = 39.098 + 14.007 + 3\times 15.999 = 101.102\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of the process = Number of moles of \text{KNO}_3 dissolved:

\displaystyle n = \frac{m}{M} = \frac{21.45}{101.102} = 0.212162\;\text{mol}.

What's the enthalpy change of this process?

Q = C\cdot \Delta T = 0.505 \times (25.00 - 14.14) = 5.4843\;\text{kJ} for 0.212162\;\text{mol}. By convention, the enthalpy change \Delta H measures the energy change for each mole of a process.

\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

4 0
3 years ago
Where is the carbon in a temperate
tangare [24]

In the high temperate

8 0
3 years ago
An object floats im sea water more readily because of sea water’s
Taya2010 [7]
Because of the sea waters density. If an object is less dense than the water it would not float
7 0
3 years ago
Read 2 more answers
In testing the effectiveness of an antacid compound, 20.0g of Hydrochloric Acid is mixed with 28.0g of Magnesium Hydroxide. Will
BartSMP [9]

Answer:

Base Mg(OH)2 does neutralise the acid and is 12g in excess.

Explanation:

2HCL +Mg(OH)2 -> MgCl2 + 2H20

2 * 36.458 g of HCL react with  58.319 g of  Mg(OH)2 to neutralise it.

72.916 HCl reacts with  58.319 g of the base.

So 20 g HCl reacts with  (58.319/72.916) * 20 = 16g.

There are 28 g of Mg(OH)2 so the base does neutralise all the acid.

The Mg(OH)2 is 28 - 16 = 12 g in excess.

4 0
3 years ago
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