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grigory [225]
3 years ago
10

The photographs show comb jellies and an anglerfish in a benthic ecosystem

Chemistry
1 answer:
Alekssandra [29.7K]3 years ago
8 0

The organism in the bethic zone can survive in such high pressure area. This is because the organism there have no air pockets that provides them the ability to be balanced in the water

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In your own words, please describe the difference between a complete ionic equation and a net ionic equation.
beks73 [17]

Explanation:

In the molecular equation for a reaction, all of the reactants and products are represented as neutral molecules (even soluble ionic compounds and strong acids). In the complete ionic equation, soluble ionic compounds and strong acids are rewritten as dissociated ions.

The net ionic equation is a chemical equation for a reaction that lists only those species participating in the reaction. The net ionic equation is commonly used in acid-base neutralization reactions, double displacement reactions, and redox reactions.

6 0
3 years ago
Which property is common to noble gases?
Flauer [41]
The answer is LOW REACTIVITY
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Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. At 24ºC and an atmospheric pres
Yanka [14]

Answer:

its 0.163 g

Explanation:

From the total pressure and the vapour pressure of water we can calculate the partial pressure of O2​

PO 2 =P t −P H 2 O

​= 760 − 22.4

=  737.6 mmHg

From the ideal gas equation we write.

W= RT/PVM = (0.0821Latm/Kmol)(273+24)K(0.974atm)(0.128L)(32.0g/mol/) =0.163g

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3 years ago
Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol2870 kJ/mol ( Δ????°
MaRussiya [10]

Answer:

Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17

Explanation:

Energy released during the complete combustion of 1 mole glucose = 2870 kJ

Energy required/muscle contraction cycle = 67 kJ/contraction

Energy conversion efficiency = 39%

Actual amount of energy converted to contraction per mole of glucose is:

=\frac{39}{100} *2870 kJ=1119.3 kJ

Total contraction cycles fueled by the above energy is:

=\frac{1119.3\ kJ}{67\ kJ/contraction} =16.7\ i.e.\ around\ 17\ contractions

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