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Natali [406]
3 years ago
15

Please please help find height and volume of pyramid!!!

Mathematics
2 answers:
ki77a [65]3 years ago
7 0

Answer:

<u>Height of the pyramid:</u>

  • h = \sqrt{22.1^2 - (28/2)^2} = \sqrt{292.41} = 17.1 m

<u>Volume:</u>

  • V = 1/3Bh
  • V = 1/3*28²*17.1 = 4468.8 m³
geniusboy [140]3 years ago
5 0

FORMULA:

Volume of pyramid = L × B × H/3

Height of pyramid = 3V/area of base(L × B)

ANSWER:

So, we have to just plug the respective value.

Height of given pyramid = √(22.1² - 14²)

  • √(488.41 - 196)
  • √292.41 = 17.1m

Now, Volume of given pyramid = 28 × 28 × 17.1/3

  • 784 × 17.1/3
  • 4468.8m³
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The sum of the measures of the angles of a polygon of n sides is 180(n - 2).

Set that expression equal to 1800 and solve for n, the number of sides.

180(n - 2) = 1800

Divide both sides by 180

n - 2 = 10

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The polygon has 10 sides.
3 0
3 years ago
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20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
3 years ago
Consider the following sequence of numbers.
Leto [7]

Answer:

Blank 1 is -3

Blank 2 is 183

Step-by-step explanation:

Let r be common ratio

r =  \frac{ - 9}{3}  \\ r =  - 3

Sum of first 5 terms

s =  \frac{a( {r}^{n}  - 1)}{r - 1}  \\ s =  \frac{  3( {( - 3)}^{5} - 1)  }{ - 3 - 1}  \\ s = 183

7 0
4 years ago
Read 2 more answers
Can someone help me plz​
alexandr1967 [171]

Answer:

B. & E.

Step-by-step explanation:

First, to find your slope, put your line into slope-intercept form.

y=mx+b\\

3x-4y=7\\-4y=-3x+7\\y=\frac{3}{4} x-\frac{7}{4}

Your slope is \frac{3}{4}.

Now, you can find the y-intercept of your parallel line by plugging your given point and your slope into point-slope form.

y-y1=m(x-x1)\\y-(-2)=\frac{3}{4} (x-(-4))\\y+2=\frac{3}{4} (x+4)\\y+2=\frac{3}{4} x+3\\y=\frac{3}{4} x+1

Your y-intercept is 1.

If you notice, answer choice E is equivalent to one of our steps in converting it to point-slope form. Therefore, E is one of your answers.

The equation of your parallel line is:

y=\frac{3}{4} x+1

B is also a correct answer.

If you put B into slope-intercept form, you get the following:

3x-4y=-4\\-4y=-3x-4\\y=\frac{3}{4} x+1

This, of course, is equivalent to the parallel line which we already found, so we know it is parallel.

7 0
4 years ago
Read 2 more answers
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