PLEASE HELP ME THIS IS DUE TODAY AND I AM DEPRESSED ( uhm look at photo )

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

4 0

Answer:

C. 19

B. 47

C. 12

C. 10

C. -8

Step-by-step explanation:

for each equation you take the number given, input it as the value of the variable, and evaluate the equation

hopefully this helps :)

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I don't know which one is it.

lorasvet [3.4K]

The answer i think is A hope that help

7 0

3 years ago

A cone has a radius of 24 cm and a volume of 1,920 cm cubed. What is the Volume of a similar cone with a radius of 18 cm?

Maurinko [17]

24 * 3/4 = 18

The radius of smaller cone is 3/4 the radius of original cone, so since these cones are similar, height must also be 3/4 times smaller.

So since radius is squared and we also multiple the height (V = 1/3 π r² h),
the volume of smaller cone would be 3³ / 4³ = 27 / 64 times smaller

So we have 1920 * (27 / 64) = 810.

Final answer: B

8 0

3 years ago

Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1

kondaur [170]

$f$ will be increasing on the intervals where $f'(x)>0$ and decreasing wherever $f'(x)$ . Local extrema occur when $f'(x)=0$ and the sign of $f'(x)$ changes to either side of that point.

$f'(x)$ is positive when $x$ is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that $f(x)$ is increasing on the intervals [-4, -2] and (2, 4].

$f'(x)$ is negative when $x$ is between some number between -2 and -1, up to some number less than 2. So $f(x)$ is decreasing on the interval [-1, 1].

You then have two possible cases for extrema occurring. The sign of $f'(x)$ changes for some $x$ between -2 and -1, and again to either side of $x=2$ .