I'm pretty sure that this is a trick question, the answer is 61%.
Given :
An equation, 2cos ß sin ß = cos ß .
To Find :
The value for above equation in (0, 2π ] .
Solution :
Now, 2cos ß sin ß = cos ß
2 sin ß = 1
sin ß = 1/2
We know, sin ß = sin (π/6) or sin ß = sin (5π/6) in ( 0, 2π ] .
Therefore,
Hence, this is the required solution.
Answer:
The slope intercept form: y = - 5x + 7
Step-by-step explanation:
The equation of line f is y − 9 = -5(x + 7)
You need to find the slope of line f
y - 9 = -5(x + 7)
In point slope form: y - y1 = m(x - x1) where m = slope
In the line f, slope m = -5
Parallel lines, slope is the same so slope of line g is also equal - 5
Line g passes through (3, - 8) so equation in point slope form:
y + 8 = -5(x - 3)
y + 8 = -5x + 15
y = -5x + 7 <-----this is slope intercept form
A solution can be found using substitution by substituting the ordered pair into both of the original equations.
Answer:
x=m+12g
Step-by-step explanation:
m=-12g+x
making x subject of formula, we have,
x=m+12g
