Answer:
(0,-1),(1,0),(2,1),(3,2)
Step-by-step explanation:
We are given that a relation
y=x+1y=x+1
We have to find the four points contained in the inverse
The given function is linear function
Therefore,
Domain of function=R
Range of function=R
x=y-1x=y−1
Now, replace x by y and y replace by x
y=x-1y=x−1
Now, substitute y=f^{-1}(x)=f
−1
(x)
f^{-1}(x)=x-1f
−1
(x)=x−1
It is linear function and defined for all real values.
Substitute x=0
f^{-1}(0)=-1f
−1
(0)=−1
Substitute x=1
f^{-1}(1)=1-1=0f
−1
(1)=1−1=0
f^{-1}(2)=2-1=1f
−1
(2)=2−1=1
f^{-1}(3)=3-1=2f
−1
(3)=3−1=2
Therefore, four points contained in the inverse (0,-1),(1,0),(2,1) and (3,2)
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Answer:
The answer is...
Step-by-step explanation:
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Number 1 is 48,
Number 2 is 9.375
Number 3 is 1.6
Number 4 is 6
ANSWER
T(-2,1)
EXPLANATION
Let T(a,b) be the coordinates.
When this point is rotated 90° counterclockwise about the origin,
Then,
If this point is then translated using the rule;
then,
It was given that, T"(-2,5)
This implies that,
-b-1=-2
-b=-2+1
-b=-1
b=1
a+7=5
a=5-7
a=-2
Therefore the coordinates of T are:
(-2,1)
