Well... if the predator would become extinct, the population of the hunted will grow and reproduce. There for it would increase.
Answer:
The correct answer to the question: What did the Clean Air Act allow citizens to do that no previous U.S. environmental law had allowed, would be: it was the first law that considered citizen lawsuits against the correct enforcement of the statutes stated in the Act.
Explanation:
The Clean Air Act, which was passed originally in 1963, and which has been amended since, with its last update being in the 1990´s, became the first time that the U.S government not only established federal funding for environmental issues, but also regulated environmental topics through EPA (Environmental Protection Agency, 1970) and considered the power that citizens could have to ensure the enforcement of the statutes and provisions considered in the Act. This consideration of citizen suits, is the most important and relevant difference with earlier environmental laws.
Answer:
Explanation:
"Which three components are common to all amino acids? The key elements of an amino acid are carbon (C), hydrogen (H), oxygen (O), and nitrogen (N), although other elements are found in the side chains of certain amino acids."
Answer:
Some versions have more steps, while others may have only a few. However, they all begin with the identification of a problem or a question to be answered based on observations of the world around us.
Explanation:
please give brainliest
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
