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nasty-shy [4]
4 years ago
7

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. –2y2 + 6y = –2

Mathematics
1 answer:
Volgvan4 years ago
5 0
For this case we have the following equation:
 -2y2 + 6y = -2
 Rewriting we have:
 -2y2 + 6y + 2 = 0
 Using the quadratic formula we have:
 x = (- b +/- root (b ^ 2 - 4 * a * c)) / (2 * a)
 Substituting values:
 x = (- (6) +/- root ((6) ^ 2 - 4 * (- 2) * (2))) / (2 * (- 2))
 Rewriting:
 x = (- 6 +/- root (36 + 16)) / (- 4)
 x = (- 6 +/- root (52)) / (- 4)
 x = (- 6 +/- root (4 * 13)) / (- 4)
 x = (- 6 +/- 2 * root (13)) / (- 4)
 x = (- 3 +/- root (13)) / (- 2)
 The roots are:
 x1 = (- 3 - root (13)) / (- 2)
 x2 = (- 3 + root (13)) / (- 2)
 Rewriting:
 x1 = -0.3
 x2 = 3.3
 Answer:
 
–0.3, 3.3
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Round to the nearest whole number<br> 74.64
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75 is the answer since the 6 is above 5.
5 0
3 years ago
Order these number (smallest to largest)<br><br><br> 35.6 0.356 35.63 3.65 356.06 356.6
Alenkinab [10]

Answer: 0.356, 3.65, 35.6, 35.63, 356.06, 356.6

Step-by-step explanation:

8 0
3 years ago
Given f(x)=3x-2 and g(x)=-1/3x +2/3, determine if g(x) and f(x) are inverse functions?
marin [14]
When dealing with inverse functions, I like to put them in terms of x and y to make it easier. y=3x-2 and y=-1/3x+2/3
to find the inverse of a function, one method is to switch the variables and then solve for the same variable as the first time, so the inverse of y=3x-2 is x=3y-2, which we now solve for y again.
x=3y-2 => x+2=3y => y=1/3x+2/3 which is not the same as y=-1/3x+2/3
Final answer:
No, f(x) and g(x) are not inverse functions.
Hope I could help :)
7 0
4 years ago
Please help!!!
ki77a [65]

Answer:

312

Step-by-step explanation:

First we need to determine the width

A = l*w

6.2 * 10 ^3 = 1.55 * 10 ^2 * w

Divide each side by 1.55 * 10 ^2

6.2 ^ 10 ^3  /1.55 * 10 ^2 = 1.55 * 10 ^2 * w / 1.55 * 10 ^2

Changing from scientific notation to standard

6200/155 = w

40 = w

Then we need to determine the perimeter

P = 2(l+w)

P = 2( 155+40)

P =2( 195)

P = 390

Now multiply by the price

390 *.80

312

7 0
3 years ago
State the number of possible real zeros and turning points of f(x) = x7 – 6x6 + 8x5. Then determine all of the real zeros by fac
Rudiy27

Answer:

steps below

Step-by-step explanation:

f(x) = x⁷ – 6x⁶ + 8x⁵

f'(x) = 7x⁶ - 36x⁵ + 40x⁴

      = x⁴ (7x² - 36x + 40)   ... (1)

Critical point (x,y): x = 0  ,  x = (36 ± √(-36)²-4*7*40) / (2*7) = (18±2√11) / 7

x = 0   or   x = 3.5    or    x = 1.6

plug into (1): y = 0   ,  y = -394.3  ,    y = 10.1

extreme : <u>maximum (1.6 , 10.1)</u>       <u>minimum (3.5 , -394.3)</u>  ... turning points

x⁷ – 6x⁶ + 8x⁵ = x⁵ (x² - 6x + 8) = x⁵ (x-2) (x-4) =0

<u>real zeros: x = 0,   x=2,    x=4</u>

3 0
3 years ago
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