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3 years ago

Kat sold cell phones for $60. She increased the price by 100%. What is the new price of the cell phones?

2 answers:

7 0

The new price is $120. 100% of $60 is $60, and because she increased by 100%, the answer is 60 (original price) +60 (price increase)

ki77a [65]3 years ago

5 0

The new price would be $120

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What is the standard equation for a circle with the center (2,1) and passing through (0, 1)

Volgvan

The radius is the distance from the center to any point. The distance from (2,1) to (0,1) is of course 2. The general formula for a circle with radius r and center (a,b) is

$(x-a)^2 + (y-b)^2 = r^2$

In our case we get

$(x-2)^2 + (y-1)^2 = 4$

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3 years ago

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at 5pm two hip started sailing toward each other from ports which were 300 miles apart at average rates of 20 and 25 mes per hou

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If the average rates were 20 and 25 miles per hour, then together they cover 45 miles of the distance they are separated by per hour. The ships will be 30 miles apart when 270 miles have been covered, so it takes 270/45=6 hours to cover the distance. 6 hours after 5 PM is 11:00 PM.

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3 years ago

Please answer as soon as possible!!

harkovskaia [24]

Answer:

2.29

Step-by-step explanation:

First determine the square root of 17.8

√17.8 = 4.22

second, determine the value of $1.3^{2.5}$ = 1.93

subtract 1.93 from 4.22

4.22 - 1.93 = 2.29

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3 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

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Question is in the Picture. A B C D

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