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2 years ago

Which of the following is a perfect square? A. 400 B. 210 C. 37 D. 199

Mathematics

2 answers:

goldenfox [79]2 years ago

5 0

Answer:

400

...

..............

Marrrta [24]2 years ago

5 0

It’s A 400

Because if you divide 400 divided 4 you will get 100. The square sides are all equal, so each side has to be 100.

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If PQ = 6x - q and PR = 15x - 29, then QR =?

Pepsi [2]

$\begin{gathered} PQ=6x-1 \\ PR=15x-29 \\ QR=? \\ QR=PR-PQ \\ QR=15x-29-(6x-1) \\ QR=15x-29-6x+1 \\ QR=9x-28 \\ 2PQ=PR \\ 2(6x-1)=15x-29 \\ 12x-2=15x-29 \\ 12x-15x=-29+2 \\ -3x=-27 \\ x=\frac{27}{3} \\ x=9 \\ QR=9(9)-28 \\ QR=81-28 \\ QR=53 \\ \text{The value of QR is 53} \end{gathered}$

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1 year ago

A student solves a quadratic and gets solutions of x=-7 and x=8. Could the discriminant of this equation equal -188?

MrMuchimi

Answer:

Step-by-step explanation:

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2 years ago

The incubation time for Rhode Island Red chicks is normally distributed with a mean of 21 days and a standard deviation of appro

34kurt

Answer:

a - c

Step-by-step explanation:

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2 years ago

Alex buys 24 apples and when he opens it 6 apples are bad whats the perecentage of the bad apples

marin [14]

It is 25 percent because 6 goes into 24 4 times

8 0

3 years ago

Read 2 more answers

Find f. A) 7.4 B) 8.2 C) 10.5 D) 11.1

tatyana61 [14]

F=72

g=6

------------

$\cos { \left( F \right) } =\frac { { e }^{ 2 }+{ g }^{ 2 }-{ f }^{ 2 } }{ 2eg }$

Therefore:

$\cos { \left( 72 \right) } =\frac { { e }^{ 2 }+{ 6 }^{ 2 }-{ f }^{ 2 } }{ 2\cdot e\cdot 6 } \\ \\ \cos { \left( 72 \right) } =\frac { { e }^{ 2 }+36-{ f }^{ 2 } }{ 12e }$

$\\ \\ 12e\cdot \cos { \left( 72 \right) } ={ e }^{ 2 }+36-{ f }^{ 2 }\\ \\ \therefore \quad { f }^{ 2 }={ e }^{ 2 }-12e\cdot \cos { \left( 72 \right) } +36\\ \\ \therefore \quad f=\sqrt { { e }^{ 2 }-12e\cdot \cos { \left( 72 \right) +36 } } \\ \\ \therefore \quad f=\sqrt { e\left( e-12\cos { \left( 72 \right) } \right) +36 }$

But what is e?

E=76

G=32

g=6

And:

$\frac { e }{ \sin { \left( E \right) } } =\frac { g }{ \sin { \left( G \right) } }$

Which means that:

$\frac { e }{ \sin { \left( 76 \right) } } =\frac { 6 }{ \sin { \left( 32 \right) } } \\ \\ \therefore \quad e=\frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } }$

If you take this value into account, you will discover that f is...

$f=\sqrt { \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } \left( \frac { 6\cdot \sin { \left( 76 \right) } }{ \sin { \left( 32 \right) } } -12\cos { \left( 72 \right) } \right) +36 } \\ \\ \therefore \quad f=10.8\quad \left( 1\quad d.p \right)$

So I would have to say that the answer is approximately (c).

6 0

2 years ago