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Naddik [55]
3 years ago
13

I will mark brain Can someone help me do not answer if u dont know

Mathematics
2 answers:
meriva3 years ago
6 0

Answer:

1. y = 1/3x+-1

2. y = 4

Hope this helps man :D

Otrada [13]3 years ago
4 0
I was about to answer until i saw someone already did ! good luck tho
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I’ll give brainliest (worth 15 pts)
mixas84 [53]

Answer:

48

Step-by-step explanation:

( it might be wrong pls dont report me just let me kno y its wrong )

3 0
3 years ago
7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th
vampirchik [111]

Solution :

Let x be student will be left handed

P = 0.09

Using the normal approximation to binomial distribution,

a). n = 108,

    μ = np = 9.72

    $\sigma = \sqrt{np(1-p)}$

       $=\sqrt{8.8452}$

       = 2.9741

Required probability,

P(x=8) = P(7.5 < x < 8.5)

$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

$=P(-0.75 < z < -0.41)$

Using z table,

= P(z<-0.41)-P(z<-0.75)

= 0.3409-0.2266

= 0.1143

b). P(x=12) = P(11.5 < x < 12.5)

$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

$=P(0.60 < z < 0.94)$

Using z table,

= P(z< 0.94)-P(z< 0.60)

= 0.8294 - 0.7257

= 0.1006

7 0
3 years ago
Simplify the expression: 4(5 - n) + 10n <br>​
irinina [24]

Answer: 6n+20

<u>Distribute</u>

<u></u>(4)(5)+(4)(-n)+10n\\20+-4n+10n<u></u>

<u></u>

<u>Combine Like Terms</u>

<u></u>20+-4n+10n\\(-4n+10n)+(20)\\6n+20<u></u>

3 0
3 years ago
Find the value of x. The diagram is not to scale.<br> 110°<br> 57°
Anika [276]

Answer:

you have to show the diagram ...

Step-by-step explanation:

4 0
4 years ago
Look in attachment ..answer if u know only pls
timurjin [86]
First of all, you have to understand g<span> is a square-root function. 

</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative. 
</span>
In other words, for any square-root function q and any input c in the domain of q (except for its endpoint), we know that this equality holds:  lim \ q(x)=q(c) 

Let's take \sqrt{x} <span>as an example. 
</span>
The domain of \sqrt x is all real numbers such that x \geq 0.  Since x=0  is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach 0 <span>from the left). 
</span>
<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value: 
</span>
lim \  \sqrt{x} =  \sqrt{0} =0 

In conclusion, the equality lim \ q(x)=q(c) holds for any square-root function q and any real number c  in the domain of q e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>

The input x=-3,  is within the domain of g<span>. 
</span>
Therefore, in order to find  lim \ g(x)  we can simply evaluate g at x-3<span>. 
</span>
g(x) 

\sqrt{7x+22} 

\sqrt{7(-3)+22} 

\sqrt{1} =1
3 0
3 years ago
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