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3 years ago

A. 6 units B. 12 units C. 21 units D. 25 units Pls help :(

Mathematics

1 answer:

valentina_108 [34]3 years ago

7 0

D. 25 units
They all meet on the graph at that point

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$\large \boxed{y = (x - 5)^{2} + 2 }$

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y = x² - 10x + 27

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$\begin{array}{rcll}y & = & x^{2} - 10x + 27 & \\y - 27 & = & x^{2} - 10x & \text{Subtracted 27 from each side}\\y - 27&= & x^{2} - 10x + 25 - 25 & \text{Added and subtracted (b/2)}^{2}\\y - 27&= & (x - 5)^{2} - 25 & \text{Wrote the first three terms as the square of a binomial}\\y& = & \mathbf{(x - 5)^{2} + 2} & \text{Added 27 to each side}\\\end{array}\\\text{The vertex form of the parabola is $\large \boxed{\mathbf{y = (x - 5)^{2} + 2 }}$}$ The figure below shows that your parabola has its vertex at (5,2).

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The table represents the start of the division of 15x3 + x2 - 3x + 2 by 3x + 2.

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The result of dividing $15x^{3}+x^{2}-3x+2$ by $3x+2$ is $5 x^{2} -3x+1$ with no remainder. Please check the step by step procedures in the picture attached.
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The remainder of the division is $0$
The divisor is $3x+2$
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