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uysha [10]
3 years ago
10

Roberta is on a hiking trip. On the first day, she starts hiking at an elevation of 223.3 feet. By the end of the first day, her

elevation increases by 276.8 feet. On the second day, her elevation decreases by 59.2 feet. On the third day, her elevation decreases by 76.3 feet. What is Roberta's elevation at the end of the third day?
Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:364.6

Step-by-step explanation:

You might be interested in
1)
vaieri [72.5K]

Answer:

see explanation

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

8 - 6 = 10 - 8 = 2

This indicates that the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 6 and d = 2, thus

a_{n} = 6 + 2(n - 1) = 6 + 2n - 2 = 2n + 4 ← explicit formula

Hence

a_{130} = (2 × 130) + 4 = 260 + 4 = 264

8 0
3 years ago
At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
80 - [50 - {20 ÷ 2 – (16 - 2÷ 2) ÷ 3}]
trapecia [35]

Answer:

35

Step-by-step explanation:

We have to solve the problems in the parenthesis first.

(16-2÷2)= (16-1)=(15)

20÷2-15÷3

(20÷2)-(15÷3)

10-5=5

50-5= 45

80-45= 35

Hope this helps!

6 0
3 years ago
Solve the differential equation y prime equals the product of 2 times x and the square root of the quantity 1 minus y squared .
MatroZZZ [7]

Answer:

1. y = sin(x²+C)

2. see below

Step-by-step explanation:

1. \frac{dy}{dx} = 2x\sqrt{1-y^2}

separation of variables

\frac{dy}{\sqrt{1-y^2} } = 2xdx

integration both sides\int\frac{dy}{\sqrt{1-y^2} } = \int2xdx

you should get :

sin^{-1} (y) = x^2+C remember constant of integration!!

2. y = sin(x²+C)

3 = sin(0+C)

y(0) = 3 does not have a solution because our sin graph is not shifted vertically or multiplied by a factor whose absolute value is greater than 1, so our range is [-1,1] and 3 is not part of this range

4 0
4 years ago
Please help me!!! I need it
ziro4ka [17]

Answer:

0.35865 and 0.35867

Step-by-step explanation:

for this number, the hundreths thousandths place is

0.358659 (bolded)

so, since the 9 rounds up, the estimated number would be 0.35866

the numbers before would be 0.35865 and after, 0.35867

6 0
3 years ago
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