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larisa [96]
2 years ago
13

A square is inscribed in a circle. How much larger is the area of the circle than the area of the square?

Mathematics
1 answer:
Orlov [11]2 years ago
3 0

Answer:

π/2 : 1 or π : 2

Step-by-step explanation:

In the attachments I have a picture of a square inscribed in a circle.

Call the side of the square a. Therefore, the area of the square is a^2.

We can also see that the diagonal of the square is the circle's diameter.

Using the Pythagorean Theorem we find that the diagonal/diameter of the circle is a√2. Thus the radius is that divided by 2, which is (a√2)/2.

We also know that the formula for a circle's area is πr^2, so the area of the circle is π((a√2)/2)^2 --> π(a^2)(2)/4 --> π(a^2)/2.

Hence the ratio of the circle to the square is π(a^2)/2 to a^2 which is π/2 to 1 or π to 2.

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Carlos is correct

Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.

Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.

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3 years ago
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Eduardwww [97]

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152%

Step-by-step explanation:

hope this helps!

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Answer:

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Step-by-step explanation:

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