-5/13
Formula: Y2-Y1/X2-X1
Answer:
The mean age of the frequency distribution for the ages of the residents of a town is 43 years.
Step-by-step explanation:
We are given with the following frequency distribution below;
Age Frequency (f) X 
0 - 9 30 4.5 135
10 - 19 32 14.5 464
20 - 29 12 24.5 294
30 - 39 20 34.5 690
40 - 49 25 44.5 1112.5
50 - 59 53 54.5 2888.5
60 - 69 49 64.5 3160.5
70 - 79 13 74.5 968.5
80 - 89 <u> 8 </u> 84.5 <u> 676 </u>
Total <u> 242 </u> <u> 10389 </u>
Now, the mean of the frequency distribution is given by the following formula;
Mean =
=
= 42.9 ≈ 43 approx.
Hence, the mean age of the frequency distribution for the ages of the residents of a town is 43 years.
Answer:
556, 558, and 560
Step-by-step explanation:
1674/3 = 558 (An even number, yay)
So 558 + 558 + 558 = 1674
Subtract two from the first one and add two to the last (still equal)
556 + 558 + 560
adding them equals 1674 so the answer is
556, 558, and 560
Answer:
12.50x less than or equal to $200
Step-by-step explanation:
A minor league plays 101 games,
They win 14 more than twice as many as they lost.
How many wins and loses?
Okay, simple.
First, write a simple addition equation. In this case wins = w and losses = l.
l + w = 101.
Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
l = l
w = 2l +14 (14 more than twice the amount)
Okay. So plug in the new amount for w.
l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
put similar terms together.
3l + 14 = 101
3l = 87
l = 29
So, we have 29 loses, and
w = 2(29) + 14
72 wins!
To check,
72 + 29 = 101, correct!
Hope this helps!