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Brums [2.3K]
3 years ago
9

What does 2×+3y=6 look like if it was plotted as a point on a graf

Mathematics
2 answers:
Troyanec [42]3 years ago
6 0
Slope: - 2/3
Graph the line using the slope and y-intercept or two points

wel3 years ago
5 0
You can change it to Slope-Intercept form. That’s what I do as it’s easier to tell what is the slope and the y-intercept.

y=mx+b

2x + 3y = 6
3y = -2x + 6
y = -2/3x + 2


Steps:

Isolate y (move 2x to the other side) and change the sign of 2x (positive to negative). Divide everything in the equation by 3 in order to get y by itself.


Now that you have the equation, the slope is -2/3 and the y-intercept is 2. What I would do it start at 2 on the y axis and go down 2 units and to the right 3 units. The other way would be start at 2 on the y axis and go up 2 units on the y axis and then to the left 3 units. Your line should be a straight, diagonal line going down (in \ <— direction).


Hope this helped!! Tried to be as informative as possible.
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A 65-story office tower has a height of 910 feet. Write an expression to find the height of each story. Then, use the expression
gizmo_the_mogwai [7]
Assuming each story is the same height
910=65 stories put together
910=65 times (height of each story)
910=65h
divide both sides by 65
14=h
each story is 14 feet

the equation is 910=65h
4 0
4 years ago
Read 2 more answers
A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po
igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b) Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

X_{2}=110 represent the number of people with the characteristic 2  

n_{1}=200 sample 1 selected  

n_{2}=150 sample 2 selected  

p_{1}=\frac{170}{200}=0.85 represent the proportion estimated for the sample 1  

p_{2}=\frac{110}{150}=0.733 represent the proportion estimated for the sample 2  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

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mafiozo [28]

Answer:

something that motivates me is music

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3 0
3 years ago
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Alika [10]

Answer:

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Step-by-step explanation:

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4 0
4 years ago
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Sue has $2.10 in dimes and nickels. If she has 12 more dimes than nickels, how many of each coin does she have?
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dimes: 21
nickels: 9
8 0
3 years ago
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