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just olya [345]
3 years ago
10

Solve the given system of equations. - 3a = 36 10a + 3c = 9 2b + 50 = 23

Mathematics
1 answer:
Elodia [21]3 years ago
5 0

Answer:

Solve using the substitution method! Answer down below:)

Step-by-step explanation:

(a,b,c) = ( -12, -27/2,43)

Hope it helps:)

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Step-by-step explanation:

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Which ordered pairs in the form (x, y) are solutions to the equation
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Answer:

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2 years ago
Read 2 more answers
What two partial products would you add to find 513 x 46
Afina-wow [57]
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

    513
    x46
--------------------------
      18 (as 6*3 = 18)
      60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
    120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
    400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)


Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
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3 years ago
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5 0
3 years ago
-8, 1, 10...<br> n<br> What is a formula for the ninth term of the given sequence
krek1111 [17]

9514 1404 393

Answer:

  a9 = -8 +9(9 -1)

Step-by-step explanation:

The given sequence has a common difference of 1-(-8) = 10-1 = 9, and a first term of -8. The formula for the n-th term of such an arithmetic sequence is ...

  an = a1 +d(n -1) . . . . . first term a1, common difference d

For the parameter of this sequence, a1=-8 and d=9, the n-th term is ...

  an = -8 +9(n -1) . . . . formula for the n-th term

__

Then the formula for the 9th term is ...

  a9 = -8 +9(9 -1)

6 0
3 years ago
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