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nexus9112 [7]
3 years ago
12

How do you write this in index form?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

The general form is nthroot{a} in index form looks like this: a^(1/n).

Let's rationalize the denominator first.

Doing so, we get (1/2)sqrt{2}.

In index form, the sqrt{2} = 2^(1/2).

We now have (1/2)[2^(1/2)].

Is this clear?

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Answer:

x=\frac{5}{4}

Step-by-step explanation:

2x+\frac{5}{8}=3x-\frac{5}{8}

Subtract 5/8 from both sides:-

2x+\frac{5}{8}-\frac{5}{8}=3x-\frac{5}{8}-\frac{5}{8}

2x+\frac{5}{8}-\frac{5}{8}

Add like terms:-

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3x-\frac{5}{8}-\frac{5}{8}

Rule:- \frac{a}{c} \pm \frac{b}{c}=\frac{a \pm b}{c}

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Subtract, -5-5=-10

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Cancel common factor: 2

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---------------

2x=3x-\frac{5}{4}

Now, subtract 3x from both sides:-

2x-3x=3x-\frac{5}{4}-3x

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Divide both sides by -1:-

\frac{-x}{-1}=\frac{-\frac{5}{4}}{-1}

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