Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
Using the distance formula, , what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?
Using the points given, plug them into the equation.
Plug this into a calculator and you get 6.32455532
Since you only need it up to the tenth (0.1), round up 6.32
<em>Five or more, let it soar. Four or less, let it rest.</em>
Since two is lower than four, we drop it.
Therefore, the distance between points (-2, 2) and (4, 4) is 6.3
Hope this helps ^w^