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fenix001 [56]
3 years ago
15

Bhhhbbbhhhhnjdjdjdjdjdjfjfjfnjd

Mathematics
2 answers:
Zepler [3.9K]3 years ago
7 0

Answer: whats the equation

Step-by-step explanation:

Deffense [45]3 years ago
5 0

Answer:

I cant see it which equation

Step-by-step explanation:

You might be interested in
Find the area of a circle with a radius of 6 ft. Round off your answer to one decimal point. (The formula for the area of a circ
butalik [34]

Answer:

Using 3.14   for pi  A = 113.0  ft^2

Using the pi button A = 113.1 ft^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi ( 6)^2

A = 36 pi

Using 3.14 for an approximation for pi

A = 36(3.14) = 113.04

To 1 decimal

113.0

Using the pi button

A = 113.0973355

A = 113.1

3 0
3 years ago
Which of the following expressions is equivalent to -g/h?
Stolb23 [73]
The correct answer is A
5 0
2 years ago
Read 2 more answers
Slope : - 9/7 point : ( -7,4 )
dolphi86 [110]
To form an equation with the given information, we use the formula :

y = mx + b, m being the slope and b being the y-intercept.

Since it is given that the slope is -9/7, we substitute m with -9/7.

y = -9/7x + b

To find b, we will substitute the known coordinates into the equation :
At point (-7 , 4), x = -7, y = 4

4 = -9/7 (-7) + b
4  = 9 + b
b = 4 - 9
b = -5

Now we know that b = -5, we will substitute b = -5 into the equation that we found earlier, y = -9/7 x + b :

y = - 9/7x - 5

To make it more readable, we can multiply the equation by 7:
7y = -9x - 5
7y + 9x + 5 = 0

-----------------------------------------------------------
Answer : 7y + 9x + 5 = 0
-----------------------------------------------------------
7 0
3 years ago
2x - 1/2 <br><br><br><br><br><br> Płēâšė hęł hęłp mè ï ńèèd thîš før hōmèwörk
Lynna [10]
Answer for x

2x-1/2=
2x=1/2 multiply both sides with 2
4x=1
x=1/4
7 0
3 years ago
Find the coordinates of the point of intersection of all parabolas that have equation y=x2+px +q with p+q=2020. The point of int
ioda

Answer:

(1,2021)

Step-by-step explanation:

P and q can vary subject to their sum being 2020.

Consider one parabola with p1 and q1 and another with p2 and q2.

y1=(x1)^2+(p1)(x1)+(q1)

y1=(x2)^2+(p2)(x2)+(q2)

At their intersection, the x and y coordinates are the same.

y1=y2=y

x1=x2=x

x^2+(p1)x+(q1)=x^2+(p2)x+(q2)

Solve for x

x(p1-p2)=q2-q1

x=(q2-q1)/(p1-p2)

Use the constraint that p+q=2020 to eliminate p1 and p2.

p1=2020-q1

p2=2020-q2

x=(q2-q1)/(2020-q1-2020+q2)

x=(q2-q1)/(q2-q1)

x=1

Substitute in the equation for y.

y=1^2+p(1)+q

y=2021

3 0
3 years ago
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