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DedPeter [7]
3 years ago
10

Part A: Explain why the x-coordinates of the points where the graphs of the equations y = ^2−x and y = ^4x + 3 intersect are the

solutions of the equation 2^−x = 4^x + 3.
Part B: Make tables to find the solution to 2^−x = 4^x + 3. Take the integer values of x only between −3 and 3.


Part C: How can you solve the equation 2^−x = 4^x + 3 graphically?
Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

Post a photo

Step-by-step explanation:

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Describe the following sequence as arithmetic, geometric or neither.<br> 2, 4, 8, 16, 32. . . .
grigory [225]
That is a geometric sequence.

3 0
3 years ago
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K divided by 11 is 7
Pani-rosa [81]
K/11 = 7
multiply 11 to both sides
K/11 (11) = 7(11)
multiply 7 and eleven together
K = 7(11)
Answer
K = 77


77 is your answer

hope this helps
5 0
3 years ago
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In a particular year, a total of 50,127 students studied in two of the most popular host countries when traveling abroad. If 838
Arlecino [84]

Answer:

In the most popular abroad country: 29,255 students

In the second-most one: 20,872 students

Step-by-step explanation:

Let's write the situation in an equation to help us solve this. X represents the amount of students in the second most popular country. So we know that in total, there's 50,127 students so let's make an equation that equals this. ???????=50,127. As we know, the most popular country has 8383 more students than the second one so we can write it as x+8383 and for the second most popular country, we can write it as x. We know that both of the countries students combined equal 50,127 students so we have our equation. (x)+(x+8383)=50,127 students. After solving the equation, you get x=20, 872. As we know x=the amount of students in the second most popular country which means there's 20,872 students in the second one. Additionally, for the first most popular one, the equation for the amount of students in it is x+8383 so..... 20,872+8383=Total number of students in the most popular one which is 29,255 students.

7 0
3 years ago
Evaluate the indefinite integral. <br> integar x4/1 + x^10 dx
ivann1987 [24]

Answer:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

Step-by-step explanation:

Given

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Required

Integrate

We have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Let

u = x^5

Differentiate

\frac{du}{dx} = 5x^4

Make dx the subject

dx = \frac{du}{5x^4}

So, we have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}

\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du

Express x^(10) as x^(5*2)

\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du

Rewrite as:

\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du

Recall that: u = x^5

\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du

Integrate

\frac{1}{5} * \arctan(u) + c

Substitute: u = x^5

\frac{1}{5} * \arctan(x^5) + c

Hence:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

7 0
3 years ago
#18-4: Douglas invests $550 in high-yield savings account. The account pays 2.1% simple interest annually. If he doesn't add or
kap26 [50]

Answer:

No

Step-by-step explanation:

You want to calculate the interest on $550 at 2.1% interest per year after 4 years.

The formula we'll use for this is the simple interest formula, or:

I = P x r x t

P is the principal amount, $550.00.

r is the interest rate, 2.1% per year, or in decimal form, 2.1/100=0.021.

t is the time involved, 4 years.

So, t is 4 year time periods.

To find the simple interest, we multiply 550 × 0.021 × 4 to get that:

The interest is: $46.20

3 0
3 years ago
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