Answer:
omg
I
1. 3×3×3×3 = 81
2. 2²a³
3. (-5)³ (-5×-5×-5) = -125
4. 1
5. a^m-n
II
1. 1.6807× 10⁴
2. (7×7×7) × (2×2×2×2×2×2) = 21952
3. 32²
4. 2187
5. 803025
The probability that the spinner lands on an even number or on the unshaded section is; 3/5
<h3>How to find the probability?</h3>
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
Read more about Probability at; brainly.com/question/24756209
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Hey there! I'm happy to help!
Let's say that we don't have jokers. In that case, there are 52 cards, and half of them are red (so 26 are red). The probability of pulling a red card once is 1/2 since half the cards are red.
If we pick one out, there are only 51 total cards left and 25 red cards. So, the probability of picking one again would be 25/51.
We multiply the probabilities of these two events to find the probability of them both happening.
1/2×25/51=25/102
The probability of picking two red cards in a row is 25/102 or around 24.5%.
Have a wonderful day! :D
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
Answer:
answer of this question is option A x-9 this represent solution