Answer:
The probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:

The standard deviation of this sampling distribution of sample proportion is:

The information provided here is:
<em>p</em> = 0.27
<em>n</em> = 423
As <em>n </em>= 423 > 30, the sampling distribution of sample proportion can be approximated by the Normal distribution.
The mean and standard deviation of the sampling distribution of sample proportion are:

Compute the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% as follows:


*Use a <em>z</em>-table.
Thus, the probability that the proportion of rooms booked in a sample of 423 rooms would differ from the population proportion by less than 6% is 0.9946.
Answer:
one and four fifths 1 4/5-
Step-by-step explanation:
Answer: 1.25 m
Step-by-step explanation:
Area of base = 1.2 m²
Number of gold fish = 6
Density of the tank should be = 4 fish/m³
Height of the tank= ?
4 fish = 1 m³
6 fish = 6/4 = 1.5 m³
Volume required for 6 fish is 1.5 m³
V = area of base x height (h)
1.5 = 1.2 x h
h = 1.25 m
Hence, height of the tank is equal to 1.25 m.
Answer:

Step-by-step explanation:

B - the other base;
A = 9/2 ( b + 35 ) / * 2 ( we will multiply both sides of the equation by 2 )
2 A = 9 ( b + 35 )
b + 35 = 2 A / 9
b + 35 - 35 = 2 A / 9 - 35
b = (2 A / 9 ) - 35
Answer: B ) b = 2 multiplied by A over 9 - 35