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3 years ago

BRAINLIEST + FRIEND IF U ANSWER MY QUESTION!!

Mathematics

1 answer:

S_A_V [24]3 years ago

4 0

Answer:

Republican

Step-by-step explanation:

trump20202020200202020

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If it were two hours later,it would be half as long until midnight as it would be if it were an hour later. what time is it now.

mafiozo [28]

Answer:

its 10 am I think

Step-by-step explanation:

it says 2 hours until midnight. 12 - 2 = 10

7 0

3 years ago

Read 2 more answers

Please help!! <br> What is the solution to 2x^2+x+2=0?

Aliun [14]

Answer:

your 3rd option

Step-by-step explanation:

$\frac{-1+/-\sqrt{1-4(2)(2} )}{2(2)}$

${\frac{-1+/-\sqrt{1-16} }{4}}$

${\frac{-1+/-\sqrt{-15} }{4}}$

${\frac{-1+/-i\sqrt{15} }{4}}$

8 0

3 years ago

Can someone help me out please.

KATRIN_1 [288]

Step-by-step explanation:

You need to reflect the shape along the line

5 0

2 years ago

Simplify the expression. Rewrite using only positive exponents.

Dvinal [7]

The simplified form of the given expression is $x^{18}a^{3}b^{3}$ .

The given expression is $(\frac{x^{4}a^{2}b^{3} }{x^{-2}ab^{2}} )^{3}$ .

We need to simplify the given expression.

<h3>What are the basic laws of exponents?</h3>

The basic laws of exponents are as follows:

$a^{m} \times b^{m} =(ab)^{m}$

$a^{m} \div b^{m} =(\frac{a}{b} )^{m}$

$a^{m} \times a^{n} =(a)^{m+n}$

$a^{m} \div a^{n} =(a)^{m-n}$

Now, $(\frac{x^{6}a^{2}b^{3} }{ab^{2}} )^{3}=(\frac{x^{18}a^{6}b^{9} }{a^{3}b^{6}} )$

$=x^{18}a^{3}b^{3}$

Therefore, the simplified form of the given expression is $x^{18}a^{3}b^{3}$ .

To learn more about the exponents visit:

brainly.com/question/26296886.

#SPJ1

4 0

2 years ago

Find the slope of the line that is parallel and perpendicular <br><br> -7x-2y=4

Rus_ich [418]

$\bf -7x-2y=4\implies -2y=7x+4\implies y=\cfrac{7x+4}{-2}\implies y=\cfrac{7x}{-2}+\cfrac{4}{-2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{2}} x-2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{7}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{7}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{7}}}$

now, what's the slope of a line parallel to that one above? well, parallel lines have exactly the same slope.

5 0

3 years ago