The difference of two numbers is 1. Their sum is 27. What are the two numbers?

A rectangle is 12cm long and 9cm wide . calculate the length of the diagonal

Shalnov [3]

Answer: 15 centimeters

Step-by-step explanation: You cut the rectangle into two triangles following the diagonal. You add 12 squared (144) and 9 squared (81) together. You get 225. You get the square root of 225 which is 15 and that is your answer. Basic solving for the hypotenuse.

4 0

3 years ago

Read 2 more answers

What is the square root of 50 rounded to the nearest hundredth?

tamaranim1 [39]

Let's write an inequality, such as follows: x < sqrt(50) < y. Square both sides of the equation. We get x^2 < 50 < y^2. Obviously, x is between 7 and 8. Also notice, that for integers a,b, (ab)^2/b^2, equals a^2. So let's try values, like 7.1. Using the previous fact, (7.1)^2, equals (71)^2/100. So, (7.1)^2, equals 50.41. Thus, our number is between 7 and 7.1. We find, with a bit of experimentation, that the square root of 50, is 7.07.

8 0

3 years ago

I would like to ask about question d

Marrrta [24]

6 halves is 3.
B is at 3 1/2
3 1/2 minus 3 is 1/2
D would be plotted at 1/2.

7 0

3 years ago

A right square pyramid has a slant height of 10 feet, and the length of a side

kotykmax [81]

Step-by-step explanation:

take the base square. find the diagonal

16^2+16^2 = 2*16^2= d^2

d= 16√2

half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10

6 0

2 years ago

If the original square had a side length of

irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas in the attached figure N 3, and the trinomial is $x^{2} +11x+28$

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

$Length=(x+4)\ in$

$width=(x+7)\ in$

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

$A1=(x)(x)=x^{2}\ in^2$