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Sauron [17]
3 years ago
8

Sam computed a 95% confidence interval for μ from a specific random sample. His confidence interval was 10.1 < μ < 12.2. H

e claims that the probability that μ is in this interval is 0.95. What is wrong with his claim?
A) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0.95 or 0.05.
B) A probability can not be assigned to the event of μ falling in this interval.
C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.
D) The probability that μ is in this interval is 0.05.
Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer: C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.

Step-by-step explanation: A 95% <u>Confidence</u> <u>interval</u> shows that there is a 95% confidence that the true parameter is between the lower and upper limits.

A CI is not a probability that the true parameter is in between the interval. The true parameter is either in the interval or not.

So, probability of falling between the limits is 0 (no chance of being in this interval) or 1 (100% possibility of being in this interval).

Then, "either μ is in the interval or it is not. therefore, the probability that μ is in this interval is 0 or 1." is correct.

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Susan currently has an account balance of $1,336.60. Her initial deposit on the account was $820 and it earned 4.5% simple inter
emmasim [6.3K]

The correct option will be :   14 years

<u><em>Explanation</em></u>

Current account balance of Susan is $1,336.60 and her initial deposit was $820

So, the amount of interest earned = 1336.60-820= 516.60 dollar

Formula for Simple Interest is: I= P*r*t, where I is the amount of interest, P is the initial amount, r is the rate of interest in decimal and t is the time duration in years.

Here, I= 516.60, P= 820, r=4.5% = 0.045

Now according to the above formula, we will get...

I= P*r*t\\\\ 516.60=820*0.045*t\\\\ 516.60=36.90*t\\\\ t=\frac{516.60}{36.90}= 14

So, Susan has held the account for 14 years.

3 0
3 years ago
Two ants, red ant and black ant, creeping along lines in 3-space. At time t, red ant is at point on the line
mylen [45]
A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t 
yr = 2 + 2 t 
zr = 6 + 2 t 

To represent the black ant, 
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yb = 2 + 3 t 
zb = 2 + t 

To calculate,
at t = 0 
xb - xr = -3 
yb - yr - 2-2 = 0 
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d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2 

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4 0
3 years ago
2.50c+6a=6344.50 <br> Find each variable
Ksju [112]

Answer:

c=2.4a+2537.8

a=-2.5/6c+1057.4

Step-by-step explanation:

solve for c:

2.50c+6a=6344.50

          -6a         -6a

2.50c=-6a+6344.50

/2.50       /2.50      /2.50

c=2.4a+2537.8

solve for a:

2.50c+6a=6344.50

-2.5c                -2.5c

6a=-2.5c+6344.50

/6       /6       /6

a=-2.5/6c+1057.4

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