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Sauron [17]
3 years ago
8

Sam computed a 95% confidence interval for μ from a specific random sample. His confidence interval was 10.1 < μ < 12.2. H

e claims that the probability that μ is in this interval is 0.95. What is wrong with his claim?
A) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0.95 or 0.05.
B) A probability can not be assigned to the event of μ falling in this interval.
C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.
D) The probability that μ is in this interval is 0.05.
Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer: C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.

Step-by-step explanation: A 95% <u>Confidence</u> <u>interval</u> shows that there is a 95% confidence that the true parameter is between the lower and upper limits.

A CI is not a probability that the true parameter is in between the interval. The true parameter is either in the interval or not.

So, probability of falling between the limits is 0 (no chance of being in this interval) or 1 (100% possibility of being in this interval).

Then, "either μ is in the interval or it is not. therefore, the probability that μ is in this interval is 0 or 1." is correct.

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Answer:

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Step-by-step explanation:

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The sum of the 3 angles in a triangle = 180°, thus

x + x + 3x = 180, that is

5x = 180 ( divide both sides by 5 )

x = 36

and 3x = 3 × 36 = 108

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a store is giving away $10 coupons to every 7th person to enter the store and a $25 coupon to every 18th person too emter the st
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3 years ago
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Answer:

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Find the value of each variable in the diagram below. Two choices are correct.
Murljashka [212]

Answer:

okay this question i dont know

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and if tiu substrate that

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you can give me the brainliest if u want

final answer-

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