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Sauron [17]
3 years ago
8

Sam computed a 95% confidence interval for μ from a specific random sample. His confidence interval was 10.1 < μ < 12.2. H

e claims that the probability that μ is in this interval is 0.95. What is wrong with his claim?
A) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0.95 or 0.05.
B) A probability can not be assigned to the event of μ falling in this interval.
C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.
D) The probability that μ is in this interval is 0.05.
Mathematics
1 answer:
almond37 [142]3 years ago
3 0

Answer: C) Either μ is in the interval or it is not. Therefore, the probability that μ is in this interval is 0 or 1.

Step-by-step explanation: A 95% <u>Confidence</u> <u>interval</u> shows that there is a 95% confidence that the true parameter is between the lower and upper limits.

A CI is not a probability that the true parameter is in between the interval. The true parameter is either in the interval or not.

So, probability of falling between the limits is 0 (no chance of being in this interval) or 1 (100% possibility of being in this interval).

Then, "either μ is in the interval or it is not. therefore, the probability that μ is in this interval is 0 or 1." is correct.

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Complete the square to write the quadratic expression in vertex form.
Anvisha [2.4K]

Answer:

1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $ \frac{101}{2} $

4. (x + 3)² = 27

5. (x + 4)² = 13

6.  $ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $

Step-by-step explanation:

Completion of Square: $ (x - a) ^2 = x^2 - 2ax + a^2 $

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9  [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $ \frac{29}{2} $

⇒ x² + 2(6)x + 36 = $ \frac{29}{2} $ + 36

⇒ x² + 2(6)x + 6² = $ \frac{29 + 72}{2} $

⇒ (x + 6)² = $ \frac{101}{2} $ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $ - \frac{30}{9} $ x = - 6

$ \implies x^2 -2 \bigg( \frac{15}{9} \bigg )x + \frac{225}{81} = - 6 + \frac{225}{81} $

$ \implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81} $

$ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $ is the answer.

6 0
3 years ago
How do u solve 24tenths-1 one 3 tenths
olya-2409 [2.1K]
Hey there!

24 tenths is 240
3 tenths is 30
1 one= 1
240-1=239
239-30=
209

Hope it helps!
7 0
4 years ago
841 rounded to the nearest 10th
Gennadij [26K]
841 rounded to the nearest 10th is 840...hope this helps u :)
6 0
3 years ago
Read 2 more answers
1. A set of weights includes a 5 lb barbell and 8 pairs of weight plates. Each pair, p,
lidiya [134]

Answer:

5 <= y <= 85

Step-by-step explanation:

Since the lowest weight possible is 5lbs (just the barbell and no weights) the lowest point of the range is 5lbs (the y intercept when x = 0)

The highest weight possible is 85lbs since, there is only 8 pairs of weight plates (8 is the input value) and the pairs each weigh 10lbs (the slope of the graph) + 5lbs from the barbell (y-intercept).

Using the function given, if you input 8 as the x value, you get

85 = 10(8) + 5

So the highest value of the range is 85lbs, therefore the range is 5 <= y <= 85.  

6 0
3 years ago
Dylan and Frank have designed a compression algorithm used for directions to unknown locations. In their algorithm the direction
spayn [35]

Answer:

The directions followed for each intersection in order are North, 3 times East, 2 times South

and 3 times East.

Step-by-step explanation:

For the word NASSA in their algorithm we know the direction they take in the first intersection is North (N).

The second letter is A = EEE, which means in the 3 next intersections they follow the East.

The two Ss indicate they follow South in the next 2 intersections.

And finally, they follow the East in the last 3 intersections.

Their direction choices can be summarized in North-East-East-East-South-South-East-East-East.

5 0
3 years ago
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