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Levart [38]
2 years ago
7

7. Un avión que sobre vuela el espacio aéreo del aeropuerto Olaya Herrera de Medellín, a una distancia constante de 3 km de la t

orre al aeropuerto, ¿Cuál es el lugar geométrico del trayecto que describe el avión en estar sobre vuelo circular con respecto a la torre de control?
Mathematics
1 answer:
skelet666 [1.2K]2 years ago
4 0

Answer:

La ecuación de la trayectoria circular del avión es x² + y² = 9

Step-by-step explanation:

La forma general de la ecuación de un círculo se da como sigue;

(x - h)² + (y - k)² = r²

Dónde;

(h, k) = El centro del círculo

r = El radio del círculo

Dado que la distancia del avión a la torre es constante, tenemos la trayectoria del avión = trayectoria circular

El radio, r de la trayectoria circular = 3 km

Por lo que la trayectoria circular del avión se va a definir con respecto a la torre de control, tenemos;

El centro de la trayectoria circular del avión = La torre

Las coordenadas del centro de la trayectoria circular = (0, 0)

Por lo tanto, (h, k) = (0, 0)

Sustituyendo los valores conocidos, la ecuación de la trayectoria circular del avión se convierte en;

(x - h)² + (y - k)² = r² → (x - 0)² + (y - 0)² = r² = x² + y² = 3² = 9

La ecuación de la trayectoria circular del avión. = x² + y² = 9

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