I’m thinking A. Would be the most suitable answer for this one
Answer:
a) 72.25sec
b) 6.25secs
c) after 10.5secs and 2 secs
Step-by-step explanation:
Given the height reached by the rocket expressed as;
s(t)= -4t^2 + 50t - 84
At maximum height, the velocity of the rocket is zero i.e ds/dt = 0
ds/dt = -8t + 50
0 = -8t + 50
8t = 50
t = 50/8
t = 6.25secs
Hence it will reach the maximum height after 6.25secs
To get the maximum height, you will substitute t - 6.25s into the given expression
s(t)= -4t^2 + 50t - 84
s(6.25) = -4(6.25)^2 + 50(6.25) - 84
s(6.25) = -156.25 + 312.5 - 84
s(6.25) = 72.25feet
Hence the maximum height reached by the rocket is 72.25feet
The rocket will reach the ground when s(t) = 0
Substitute into the expression
s(t)= -4t^2 + 50t - 84
0 = -4t^2 + 50t - 84
4t^2 - 50t + 84 = 0
2t^2 - 25t + 42 = 0
2t^2 - 4t - 21t + 42 = 0
2t(t-2)-21(t-2) = 0
(2t - 21) (t - 2) = 0
2t - 21 = 0 and t - 2 = 0
2t = 21 and t = 2
t = 10.5 and 2
Hence the time the rocket will reach the ground are after 10.5secs and 2 secs
Answer:
0.7 + 0.4 - 0.2 = 0.9
Step-by-step explanation:
Let's denote the probabilities as following:
The probability that the show had animals is
P(A) = 0.7
The probability that the show aired more than 10 times is
P(B) = 0.4
The probability that the show had animals and aired more than 10 times is
P(A⋂B) = 0.2
The probability that a randomly selected show had animals or aired more than 10 times is P(A⋃B)
The correct form of addition rule to determine the probability that a randomly selected show had animals or aired more than 10 times is:
P(A⋃B) = P(A) + P(B) - P(A⋂B) = 0.7 + 0.4 - 0.2 = 0.9
=> Option B is correct
Hope this helps!
Answer:
WTH is that bro, If I had to answer this between a life or death situation I'd die
Answer:
JKLM is similar to ABCD
Step-by-step explanation:
