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<h3>Final value : x² -9x - 11</h3>
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<h3>Step by step </h3>
2x + 1 = ⅕ × (x² + x - 6)
2x + 1 = ⅕x² + ⅕x - 6/5
1/5x² +1/5x - 2x - 6/5 - 1 = 0
1/5x² -9/5x - 11/5 = 0
x² - 9x - 11 = 0. #times by 5
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#Give me brainliest pls im tired typing all of this
Refrection across the y-axis changes the function to y = |-x|.
Vertical stretch by a factor of 1.5 changes the graph to y = 1.5|-x|
Shifting the graph by 4 units downward changes the graph to y = 1.5|-x| - 4
Required equation is y = 1.5|-x| - 4
Answer:
Step-by-step explanation:
Area of a square =
If l = ,
Then area =
HOPE THIS HELPS
If one of our zeros is 4, then the factor is x-4. If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i. So our 3 factors are (x-4)(x+5i)(x-5i). We will FOIL out these factors to get the polynomial. Let's start with the ones that contain the imaginary numbers. Doing that mutliplication we get x^2-25i^2. i^2 is equal to -1, so what that expression simplifies down to is
. Now we will multiply in that last factor of (x-4):
. FOILing out we have
. There you go!